The melting point. So d is ur answer. The color and texture of both is the same. They sont have magnetism. So the only logical one is melting point.
Please vote brainliest
Yo my knowledge, refraction.
Answer:
broken pieces of glass from a window can't form a shadow.
Explanation:
the reason is that shadow is formed only when light rays hits an opaque object, which doesn't let light to pass through it, but glass is a transparent object, hence light rays passes through it forming no shadow..
<em>i</em><em> </em><em>hope</em><em> </em><em>it</em><em> </em><em>helped</em><em>.</em><em>.</em><em>.</em><em>.</em>
Answer:
If the temperature of the air in the balloon is less than the temperature of the air surrounding the balloon then the balloon will appear slightly deflated because of the difference in temperature.
As the temperature of the air in the balloon reaches the surrounding air temperature, then the balloon will appear to be fully inflated because the temperature of the air in the balloon is the same as the surrounding air temperature.
<u>Hello and Good Morning/Afternoon</u>:
<em>Original Question: C₂H₅OH + __O₂ → __CO₂ + __ H₂O</em>
<u>To balance this equation</u>:
⇒ must ensure that there is an equal number of elements on both sides of the equation at all times
<u>Let's start balancing:</u>
- On the left side of the equation, there are 2 carbon molecule
⇒ but only so far one on the right side
C<em>₂H₅OH + __O₂ → 2CO₂ + __ H₂O</em>
- On the left side of the equation, there are 6 hydrogen molecules
⇒ but only so far two on the right side
C<em>₂H₅OH + __O₂ → 2CO₂ + 3H₂O</em>
- On the right side of the equation, there are 7 oxygen molecules
⇒ but only so far three on the left side
C<em>₂H₅OH + 3O₂ → 2CO₂ + 3H₂O</em>
<u>Let's check and make sure we got the answer:</u>
C<em>₂H₅OH + 3O₂ → 2CO₂ + 3H₂O</em>
<em> 2 Carbon ⇔ 2 Carbon</em>
<em> 6 Hydrogen ⇔ 6 Hydrogen</em>
<em> 7 Oxygen ⇔ 7 oxygen</em>
<u>Thefore the coefficients in order are</u>:
⇒ 1, 3, 2, 3
<u>Answer: 1,3,2,3</u>
Hope that helps!
#LearnwithBrainly<em> </em>
