it can be said that the speed of the east wind is
v=0.3608m/s
From the question we are told
A small boat sailed <u>straight </u>north out of a harbor in <em>strong </em>east wind (blowing from west to east).
After sailing for 120 minutes, it ended up hitting a buoy 60^\circ60 ∘ to the north-east of the harbor. If the straight-line distance between the buoy and the harbor is 3 km,
- what is the speed of the east wind?.
<h3> the speed of the east wind</h3>
Generally the equation for the distance is mathematically given as
BA=3000sin60
BA=2598.07m
Therefore
the speed of the east wind
v=0.3608
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Answer:
Technician A says that this is the normal operation of the ETC self -test is the correct answer.
Explanation:
An engine control unit (ECU), also widely referred to as an engine control module (ECM), is a type of electronic control device that controls an internal combustion engine with a series of actuators to ensure maximum engine performance.
It achieves so by reading values from a multitude of sensors within the engine bay, translating data using multidimensional feedback maps (the so-called lookup tables) and modifying the actuators.
Mechanically fixed and dynamically regulated by mechanical and pneumatic means, air-fuel combination, ignition time, and idle speed were before ECUs.
As soon as the system gets battery voltage, after ignition is turned, the efi computer makes a self-test of all the actuators and sensors, included the ETC.
Answer:
0 Newtons
Explanation:
The velocity of the object does not change, it is a constant 54 km/hr. When velocity does not change, acceleration is zero. Using the formula Force = mass x acceleration, we find:
mass = 1200 kg
acceleration = 0
F = (1200)(0) = 0
To find the rate of deceleration, subtract the initial velocity from the final velocity.
The equation that describes the graph is y = 16.7x + 150.
<h3>What is the equation?</h3>
We have been given the graph of a certain function data set in physics. We know that the graph is the representation of data on cartesian coordinates. In this case, we are asked to find the equation of the graph in the form; y=mx+b
m = slope of the graph
b = intercept of the graph.
To obtain the slope;
m = y2 - y1/ x2 - x1
m = 400 - 200/ 16 - 4
m = 200/ 12
m = 16.7
Then we can see from the graph that the y - intercept is 150. Having these data, the equation that could describe the graph is now;
y = 16.7x + 150
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