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2 years ago

When will you say a body is in a) uniform acceleration (b) non uniform acceleration

Physics

1 answer:

s2008m [1.1K]2 years ago

7 0

Answer:

See below ~

Explanation:

Part (a) :

We can say a body is in uniform acceleration if the acceleration of the object remains constant with respect to time throughout its motion.

Part (b) :

We can say a body is non-uniform acceleration if the acceleration of the body varies with respect to time throughout its motion.

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Which object would have the greatest acceleration?

Andre45 [30]

Answer:

Explanation:

A and C are balanced, B has a resultant force of 5N right, and D has a resultant force of 20N right.

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3 years ago

A car at the top of a ramp starts from rest and rolls to the bottom of the ramp, achieving a certain final speed. If you instead

zimovet [89]

Answer:

It must be 4 times high.

Explanation:

Assuming that the car can be treated as a point mass, and that the ramp is frictionless, the total mechanical energy must be conserved.
This means, that at any time, the following must be true:
ΔK (change in kinetic energy) = ΔU (change in gravitational potential energy)

⇒ $m*g*h = \frac{1}{2} * m*v^{2}$

Let's call v₁, to the final speed of the car, and h₁ to the height of the ramp.

So, at the bottom of the ramp, all the gravitational potential energy

must be equal to the kinetic energy of the car (Defining the bottom of

the ramp as our zero reference for the gravitational potential energy):

$m*g*h_{1} = \frac{1}{2} * m*v_{1} ^{2}$ (1)

Now, let's do v₂ = 2* v₁
Replacing in (1) we get:

$m*g*h_{2} = \frac{1}{2} * m*(2*v_{1}) ^{2}$ (2)

Dividing (2) by (1), and rearranging terms, we get:
h₂ = 4* h₁

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3 years ago

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Aneli [31]

Answer:Climatic processes affect the dynamics of Earth's ice sheets and glaciers, and along ... by abrupt events and by continuous reshaping of Earth's surface from surface ... Forecasting natural disasters, including the timing and size of earthquakes, the . Last, human activity has a profound impact on water resources, landscape

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3 years ago

Read 2 more answers

What is the strength of the electric field ep 0.90 mm from a proton?

dem82 [27]

The electric field strength is inversely related to the square of the distance.so the strength of the electric field is given by

$E=\frac{1}{4\pi \epsilon _{0} } \frac{q}{r^{2} } = \frac{k q}{r^{2} }$

Here, $\frac{1}{4\pi \epsilon _{0} } = k$ is constant depend upon medium and its value is $9.0 \times10^{9} \ N m^2/C^2$ and q is charge and r is the distance.

Given $r = 0.90 mm = 9.0 \times 10^{-4} m$ and we know the charge of proton, $q = 1.6\times 10^{-19} \ C$ .

Therefore,

$E=\frac{9.0 \times10^{9} \ N m^2/C^2 \times1.6\times 10^{-19} \ C }{(9.0 \times 10^{-4} m)^2} = 0.177 \times 10^{-2} \ N/C \\\\ E= 1.77 \times 10^{-3} N/C$