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2 years ago

Determine the number of moles of iodine that reacts with 50g of aluminum

Chemistry

1 answer:

frozen [14]2 years ago

8 0

Answer: The correct answer is option B i.e., 2.78 mol

Explanation:

Aluminium reacts with iodine to form Aluminium iodide

$2Al(s)+3I_{2}(s) \to Al_{2}I_{6}(s)$

From the equation, it is clear that 3 moles of iodine reacts with 2 moles of Aluminium to form Aluminium iodide

We know $$No.\,of\,moles=\frac{weight}{molecular\,weight} \\$

For 2 moles of Aluminium, $2=\frac{weight}{27}$\\ $weight=2 \times 27=54g$

3 moles of Iodine reacts with 54 g of Aluminium

? moles of iodine react with 50 g of Aluminium

$=\frac{3 \times 50}{54} =2.78 mol$

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The air bags in cars are inflated when a collision triggers the explosive, highly exothermic decomposition of sodium azide (NaN3

Oksanka [162]

Answer : The mass of $NaN_3$ required is, 166.4 grams.

Explanation :

First we have to calculate the moles of nitrogen gas.

Using ideal gas equation:

$PV=nRT$

where,

P = Pressure of $N_2$ gas = 1.00 atm

V = Volume of $N_2$ gas = 113 L

n = number of moles $N_2$ = ?

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of $N_2$ gas = $85^oC=273+85=358K$

Putting values in above equation, we get:

$1.00atm\times 113L=n\times (0.0821L.atm/mol.K)\times 358K$

$n=3.84mol$

Now we have to calculate the moles of sodium azide.

The balanced chemical reaction is,

$2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)$

From the balanced reaction we conclude that

As, 3 mole of $N_2$ produced from 2 mole of $NaN_3$

So, 3.84 moles of $N_2$ produced from $\frac{2}{3}\times 3.84=2.56$ moles of $NaN_3$

Now we have to calculate the mass of $NaN_3$

$\text{ Mass of }NaN_3=\text{ Moles of }NaN_3\times \text{ Molar mass of }NaN_3$

Molar mass of $NaN_3$ = 65 g/mole

$\text{ Mass of }NaN_3=(2.56moles)\times (65g/mole)=166.4g$

Therefore, the mass of $NaN_3$ required is, 166.4 grams.

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2 years ago

To find the atomic mass of a particular atom you need to know

Andreyy89

You just need the number of protons and number of neutrons as the mass of eelctrons is negligible

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2 years ago

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Answer:

In a conventional optical microscope, objects less than about 200 nanometers apart cannot be distinguished from one another. ... Although electron microscopes produce a detailed image of very small structures, they cannot provide an image of the proteins that make up those structures.

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2 years ago

Does sodium (Na) and argon (Ar) on the periodic table have similar properties? Explain in terms of location on the periodic tabl

iVinArrow [24]

Sodium (Na) and Argon (Ar) on the periodic table does not have similar properties.

PERIODIC TABLE:

Periodic table is the organized table that showcases the position of elements. The periodic table is organized into groups and periods.

Groups of the periodic table is in a vertical format labeled 1 - 7 while the period is in a horizontal format labeled 1 - 7.

Elements in the same group have the same number of valence electrons and hence, possess similar chemical properties.

Sodium (Na) belongs to group 1 while argon is a noble gas, hence, they are not in the same group of the periodic table and cannot have same properties.

Learn more at: brainly.com/question/24089206?referrer=searchResults

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2 years ago

URGENT!!!What volume of a 0.88 M solution can be made using 130. Grams of FeCI^2?

Likurg_2 [28]

Answer:

1.16L can be made

Explanation:

Molarity = Mol / Volume

Volume = Mol / Molarity

Let's determine the moles of salt, with that mass:

130 g FeCl₂ . 1mol / 126.75 g = 1.02 moles of FeCl₂

Volume = 1.02 mol / 0.88 mol/L → 1.16L

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2 years ago

Determine the number of moles of iodine that reacts with 50g of aluminum​

Determine the number of moles of iodine that reacts with 50g of aluminum