Question

Determine the number of moles of iodine that reacts with 50g of aluminum​

Answer 1

Answer: The correct answer is option B i.e., 2.78 mol

Explanation:

Aluminium reacts with iodine to form Aluminium iodide

$2Al(s)+3I_{2}(s) \to Al_{2}I_{6}(s)$

From the equation, it is clear that 3 moles of iodine reacts with 2 moles of Aluminium to form Aluminium iodide

We know $No.\,of\,moles=\frac{weight}{molecular\,weight}$

For 2 moles of Aluminium, $2=\frac{weight}{27} \\ weight=2 \times 27=54g$

3 moles of Iodine reacts with 54 g of Aluminium

? moles of iodine react with 50 g of Aluminium

$=\frac{3 \times 50}{54} =2.78 mol$