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melomori [17]
3 years ago
9

If the 3d and 4s bands overlap in a metal atom, what is the maximum number of electrons for this composite band

Chemistry
1 answer:
kolezko [41]3 years ago
8 0

Answer: 12 electrons

<u>If the 3d and 4s bands are superimposed on a metal atom, the maximum number of electrons for this band will be 12 electrons.</u> Remember that in layer 10 you can enter up to 10 electrons in the orbitals that you have, while the s can enter 2, therefore the amount of electrons that will enter the set formed by both bands when superimposed will be 12 electrons

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What is always true of an object with a lit of mass ?
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The actual yield of a certain reaction is 44.0 g, while the theoretical yield is 50.0 g. Calculate the percent yield.
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An analytical chemist is titrating of a solution of nitrous acid with a solution of . The of nitrous acid is . Calculate the pH
Burka [1]

Answer:

pH = 2.69

Explanation:

The complete question is:<em> An analytical chemist is titrating 182.2 mL of a 1.200 M solution of nitrous acid (HNO2) with a solution of 0.8400 M KOH. The pKa of nitrous acid is 3.35. Calculate the pH of the acid solution after the chemist has added 46.44 mL of the KOH solution to it.</em>

<em />

The reaction of HNO₂ with KOH is:

HNO₂ + KOH → NO₂⁻ + H₂O + K⁺

Moles of HNO₂ and KOH that react are:

HNO₂ = 0.1822L × (1.200mol / L) = <em>0.21864 moles HNO₂</em>

KOH = 0.04644L × (0.8400mol / L) = <em>0.0390 moles KOH</em>

That means after the reaction, moles of HNO₂ and NO₂⁻ after the reaction are:

NO₂⁻ = 0.03900 moles KOH = moles NO₂⁻

HNO₂ = 0.21864 moles HNO₂ - 0.03900 moles = 0.17964 moles HNO₂

It is possible to find the pH of this buffer (<em>Mixture of a weak acid, HNO₂ with the conjugate base, NO₂⁻), </em>using H-H equation for this system:

pH = pKa + log₁₀ [NO₂⁻] / [HNO₂]

pH = 3.35 + log₁₀ [0.03900mol] / [0.17964mol]

<h3>pH = 2.69</h3>
8 0
3 years ago
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