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2 years ago

If the 3d and 4s bands overlap in a metal atom, what is the maximum number of electrons for this composite band

Chemistry

1 answer:

kolezko [41]2 years ago

8 0

Answer: 12 electrons

If the 3d and 4s bands are superimposed on a metal atom, the maximum number of electrons for this band will be 12 electrons. Remember that in layer 10 you can enter up to 10 electrons in the orbitals that you have, while the s can enter 2, therefore the amount of electrons that will enter the set formed by both bands when superimposed will be 12 electrons

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Convert 15.2 moles of K to atoms of K.

choli [55]

Answer:

$\boxed {\boxed {\sf 9.15*10^{24} \ atoms \ K}}$

Explanation:

To convert atoms to moles, Avogadro's Number must be used: 6.022*10²³.

This tells us the amount of particles (atoms, molecules, etc.) in 1 mole of a substance. In this case it is the atoms of potassium. We can create a ratio.

$\frac {6.022*10^{23} \ atoms \ K }{ 1 \ mol \ K }$

Multiply by the given number of moles: 15.2

$15.2 \ mol \ K *\frac {6.022*10^{23} \ atoms \ K }{ 1 \ mol \ K }$

The moles of potassium cancel.

$15.2 *\frac {6.022*10^{23} \ atoms \ K }{ 1 }$

The denominator of 1 can be ignored.

$15.2 * {6.022*10^{23} \ atoms \ K }{$

Multiply.

$9.15344*10^{24} \ atoms \ K$

The original measurement of moles has 3 significant figures, so our answer must have the same. For the number we calculated that is the hundredth place. The 3 in the thousandth place tells us to leave 5.

$9.15*10^{24} \ atoms \ K$

In 15.2 moles of potassium, there are 9.15*10²⁴ atoms of potassium.

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this is your answer

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hope it helps

good day (≧▽≦)

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