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Answer: The value of equilibrium constant for reaction is,
Explanation:
The given chemical equations are:
(1)
;
(2)
;
Now we have to calculate the equilibrium constant for chemical equation as:
;
We are reversing reaction 2 and multiplying reaction 2 by 2 and then adding both reaction, we get the final reaction.
The equilibrium constant for the reverse reaction will be the reciprocal of that reaction.
If the equation is multiplied by a factor of '2', the equilibrium constant of that reaction will be the square of the equilibrium constant.
If we are adding equations then the equilibrium constants will be multiplied.
The value of equilibrium constant for reaction is:
Now put all the given values in this expression, we get:
Hence, the value of equilibrium constant for reaction is,
Answer:- 10 L of ethane.
Solution:- The given balanced equation is:
From this equation, ethane and oxygen react in 2:7 mol ratio, the ratio of volumes would also be same if they are at same temperature and pressure.
Since 14 L of each gas are taken, the oxygen will be the limiting reactant and ethane will be the excess reactant. Let's calculate the volume of ethane used:
=
From above calculations, 4 L of ethane are used. So, excess volume of ethane left after the completion of reaction = 14 L - 4 L = 10 L
Hence, 10 L of ethane will be remaining.