The universe contains billions of galaxies, each containing billions of stars. True or false
2 answers:
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Answer:
Explanation:
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In this case, for this neutralization reaction, it is possible to realize that one the neutralization products is water (pH=7) and the other one is the salt coming up from the cation of the NaOH and the anion of the HI:
Moreover, since the solubility of NaI is large in water, we infer it remains aqueous whereas the water is maintained as liquid:
Which is also balanced as the number of atoms of all the elements is the same at both sides.
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<u>Answer:</u> The concentration of at equilibrium is 0.00608 M
<u>Explanation:</u>
As, sulfuric acid is a strong acid. So, its first dissociation will easily be done as the first dissociation constant is higher than the second dissociation constant.
In the second dissociation, the ions will remain in equilibrium.
We are given:
Concentration of sulfuric acid = 0.025 M
Equation for the first dissociation of sulfuric acid:
0.025 0.025 0.025
Equation for the second dissociation of sulfuric acid:
<u>Initial:</u> 0.025 0.025
<u>At eqllm:</u> 0.025-x 0.025+x x
The expression of second equilibrium constant equation follows:
We know that:
Putting values in above equation, we get:
Neglecting the negative value of 'x', because concentration cannot be negative.
So, equilibrium concentration of sulfate ion = x = 0.00608 M
Hence, the concentration of at equilibrium is 0.00608 M