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Harman [31]
3 years ago
12

Which coefficient before sodium bromide (NaBr) balances this chemical equation?

Chemistry
1 answer:
yuradex [85]3 years ago
8 0

We see that in the left-hand side of the equation, the side of the reactants, that we have 2 moles of Na and bromine is in it's diatomic form.

Therefore, we have 2 moles of each of these elements. When we combine the sodium bromide molecule in the products, we are going to want to keep these molar amounts the same. So we are going to need to put a 2 in front of the sodium bromide in order to correctly balance this equation.

So the coefficient for sodium bromide (NaBr) in this equation is 2.

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Molecular weight of PbCl2 = 278 g/mole Mass of beaker + PbCl2 = 62.19 g Mass of beaker = 57.77 g Mass of PbCl2 per 100 mL = g Mo
levacccp [35]
PbCl2--->Pb2+  +  2Cl-

The  mass   of  PbCl2   is   =mass   of  the  beaker+Pbcl2  minus   mass  of  the  beaker
that  is  62.19-57.77g=  4.42grams

moles  of PbCl2=  4.42g/278g/m0l = 0.0159moles

concentration  of  (Pb2+)
since  mole  ratio  of  PbCl2  to  Pb2+  is   1:1  therefore  the  moles  of  Pb2+  is  also  0.0159moles
concentration  =0.0159/100 x1000=0.159M

concentration  of  CI-  is  two  time  that  of  Pb2+  from  the  equation  above  therefore  concentration   of  Cl-  =  0.159 x2  =0.318M
7 0
3 years ago
Which statement correctly describes the mechanism of inheritance?
Len [333]
The second one is correct. Alleles on homologous chromosomes determine traits
7 0
4 years ago
Read 2 more answers
The rate of reaction (reaction rate) is the
Lorico [155]
Sugar dissolves faster in a warm liquid than in a cold liquid – this is an example of how temperature influences the reaction rate....

Yes it is. Another example is surface area of reactants, powdered iron fillings would react faster in HCl than iron lumps.

Also your beverage would also dissolve faster in hot water than in cold water, this is also an example of how temperature affects rate of reaction.

There are other examples that can be stated as well.
3 0
4 years ago
A balloon at -73C with 5L of gas is heated to 400K. If the pressure ranges from 101.3 kPa to 1520 torr; What will be the final v
Sergio039 [100]

Answer: The final volume will be 2.89 L.

Explanation:

Given: T_{1} = 73^{o}C = (73 + 273) K = 346 K,         V_{1} = 5L,          T_{1} = 400 K

P_{1} = 101.3 kPa

Convert kPa to atm as follows.

1 kPa = 0.00986923\\101.3 kPa = 101.3 kPa \times \frac{0.00986923 atm}{1 kPa}\\= 0.99 atm\\= 1 atm

P_{2} = 1520 torr

Convert torr into atm as follows.

1 torr = 0.00131579 atm\\1520 torr = 1520 torr \times \frac{0.00131579 atm}{1 torr}\\= 2 atm

Formula used to calculate final temperature is as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}

Substitute the values into above formula as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{1 atm \times 5 L}{346 K} = \frac{2 atm \times V_{2}}{400 K}\\V_{2} = 2.89 L

Thus, we can conclude that the final volume will be 2.89 L.

7 0
3 years ago
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