My calculator is about 1cm thick, 7cm wide, and 13cm long.
Its volume is (length) (width) (thick) = (13 x 7 x 1) = 91 cm³ .
The question wants me to assume that the density of my calculator
is about the same as the density of water. That doesn't seem right
to me. I could check it easily. All I have to do is put my calculator
into water, watch to see if sinks or floats, and how enthusiastically.
I won't do that. I'll accept the assumption.
If its density is actually 1 g/cm³, then its mass is about 91 grams.
The choices of answers confused me at first, until I realized that
the choices are actually 1g, 10² g, 10⁴ g, and 10⁶ g.
My result of 91 grams is about 100 grams ... about 10² grams.
Your results could be different.
Answer:
11.85m
Explanation:
For the development of this problem we must resort to the concepts of the basic kinematic equations that define the distance of a body, such as speed for a certain time, that is,

From the information provided we say that the distance between the cretas is 0.6m,

In our information we have also that the length between the first and latest wave is in time terms of 2.2s. They are 4 waves in 3 intervals then




Then the distance from the shore is given by the speed of the waves for the total time. That is


