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3 years ago

Which of the following elements will sulfur most readily react with in order to help it fill its outer shell with 8 electrons?

Chemistry

1 answer:

Gelneren [198K]3 years ago

5 0

Answer:

Magnesium

Explanation:

Using the KLMN styled electronic configuration, the electronic configuration of sulphur with atomic number 16 is 2, 8,6

What this means is that it needs extra 2 electrons to fill into its M shell to attain the octet configuration.

Now let’s look at Magnesium, with atomic number 12, the electronic configuration it has is 2,8,2.

This means it has 2 extra electrons to give away so as to attain its own stability.

The sulphur atom will gladly accept the two electrons which the magnesium atom wants to give away. This makes it the perfect element to be reacted with sulphur to make it attain its octet configuration

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If the reaction of 3.50 moles of lithium with excess hydrofluoric acid produced a 75.5% yield of hydrogen gas, what was the actu

melomori [17]

<u>Answer: </u>The correct answer is 1.32 mol $H_2$

<u>Explanation:</u>

For the reaction of lithium and hydrofluoric acid, the equation follows:

$2Li+2HF\rightarrow 2LiF+H_2$

By Stoichiometry of the reaction:

if 2 moles of lithium is producing 1 mole of hydrogen gas,

Then, 3.50 moles of lithium will produce = $\frac{1}{2}\times 3.5=1.75mol$ of hydrogen gas.

Now, to know the theoretical yield of hydrogen gas, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ...(1)

Moles of hydrogen gas = 1.75 mol

Molar mass of hydrogen gas = 2 g/mol

Putting values in above equation, we get:

$1.75mol=\frac{\text{Mass of hydrogen gas}}{2g/mol}\\\\\text{Given mass of hydrogen gas}=3.5gl$

To calculate the percentage yield, we use the equation:

$\%\text{ yield}=\frac{\text{Actual yield}}{\text{Theoretical yield}}\times 100$

Percentage yield = 75.5 %

Theoretical yield = 3.5 g

Putting values in above equation, we get:

$75.5=\frac{\text{actual yield}}{3.5g}\times 100\\\\\text{Actual yield}=2.64g$

Now, calculating the moles of hydrogen gas, we put the value in equation 1, we get:

$\text{Moles of hydrogen gas produced}=\frac{2.64g}{2g/mol}=1.32mol$

Hence, the correct answer is 1.32 mol $H_2$

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