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4 years ago

Which of the following elements will sulfur most readily react with in order to help it fill its outer shell with 8 electrons?

Chemistry

1 answer:

Gelneren [198K]4 years ago

5 0

Answer:

Magnesium

Explanation:

Using the KLMN styled electronic configuration, the electronic configuration of sulphur with atomic number 16 is 2, 8,6

What this means is that it needs extra 2 electrons to fill into its M shell to attain the octet configuration.

Now let’s look at Magnesium, with atomic number 12, the electronic configuration it has is 2,8,2.

This means it has 2 extra electrons to give away so as to attain its own stability.

The sulphur atom will gladly accept the two electrons which the magnesium atom wants to give away. This makes it the perfect element to be reacted with sulphur to make it attain its octet configuration

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Using the reaction below: 2 CO2(g) + 2 H2O(l) → C2H4(g) + 3 O2(g) ΔHrxn= +1411.1 kJ What would be the heat of reaction for this

maw [93]

Answer: d) -705.55 kJ

Explanation:

Heat of reaction is the change of enthalpy during a chemical reaction with all substances in their standard states.

$2CO_2(g)+2H_2O(l)\rightarrow C_2H_4(g)+3O_2(g)$ $\Delta H=+1411.1kJ$

Reversing the reaction, changes the sign of $\Delta H$

$C_2H_4(g)+3O_2(g)\rightarrow 2CO_2(g)+2H_2O(l)$

$\Delta H=-1411.1kJ$

On multiplying the reaction by $\frac{1}{2}$ , enthalpy gets half:

$0.5C_2H_4(g)+1.5O_2(g)\rightarrow CO_2(g)+H_2O(l)$ $\Delta H=\frac{1}{2}\times -1411.1kJ=-705.55kJ/mol$

Thus the enthalpy change for the given reaction is -705.55kJ

7 0

3 years ago

How can you separate a solid from a liquid?

Marina86 [1]

We can use evaporation and as well filtration to separate solid to liquid.

3 0

3 years ago

How does an atom change if all of its electrons are removed?

adelina 88 [10]

Answer:

The atom becomes positively charged.

5 0

4 years ago

Determine the rate of the reaction shown directly below if the rate constant k is 1.1 x 10^–2 M^–2 s^–1, the NO concentration is

Helen [10]

Answer:

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6 0

3 years ago

For the reaction at 298 K, 2NO2(g) N2O4(g) the values of ΔH° and ΔS° are -58.03 kJ and -176.6 J/K, respectively. Calculate the v

Ierofanga [76]

Answer:

$\Delta G^o=-5.4032 kJ$

The temperature for $\Delta G^o=0[/tex is [tex]T=328.6 K$

Explanation:

The three thermodinamic properties (enthalpy, entropy and Gibbs's energy) are linked in the following formula:

$\Delta G^o=\Delta H^o + T*\Delta S^o$

Where:

$\Delta G^o$ is Gibbs's energy in kJ

$\Delta H^o$ is the enthalpy in kJ

$\Delta S^o$ is the entropy in kJ/K

$T$ is the temperature in K

Solving:

$\Delta G^o=-58.03 kJ - 298K*-0.1766 kJ/K$

$\Delta G^o=-5.4032 kJ$

For $\Delta G^o=0$ :

$0=\Delta H^o - T*\Delta S^o$

$\Delta H^o= T*\Delta S^o$

$T=\frac{\Delta H^o}{\Delta S^o}$

$T=\frac{-58.03 kJ}{-0.1766 kJ/K}$

$T=328.6 K$

3 0

3 years ago

Read 2 more answers