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3 years ago

Which is true of transition metals when moving from left to right on the periodic table?

Chemistry

2 answers:

marysya [2.9K]3 years ago

4 0

The correct option is D.

Transition metals are those metallic elements that are located in the central block of the periodic table. They exhibit various valency states and they generally have various colors. The atomic radius of an element refers to the measure of the size of its atom. For transition metals, their atomic radii decrease slightly and then start to increase, when one is moving from the left to the right of the periodic table.

beks73 [17]3 years ago

4 0

Answer : The correct option is, Atomic radii decrease slightly and then start to increase.

Explanation :

Transition metals : It is defined as the element whose atom is ground state or ion in one of the common oxidation states, has incomplete d-subshell.

The general trend of atomic radii of transition metals is :

Generally the atomic radii of d-block elements in a series decreases with increase in atomic number but decreases in atomic size is small after midway that means almost remains same and at the end of the period there is a slight increase in the atomic radii.

Hence, the atomic radii decrease slightly and then start to increase of the transition metals when moving from left to right on the periodic table.

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Explain why a lithium ion is smaller than a fluoride ion.

meriva

That is because the fluoride ion has 8 electrons and 9 protons while a lithium ion has 3 protons and 3 electrons. Therefore the lithium ion has fewer shells than flouride

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What property of a solution remains the same after it is diluted? (3 points)

madreJ [45]

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1. Amount of solvent

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Review the equation below.

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2KClO3 --> 2KCl + 3O2

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3 years ago

Read 2 more answers

Which describes bonding electrons in a polar covalent bond?

raketka [301]

Answer:

I think the third one

Explanation:

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3 years ago

If you were to use Lewis theory to predict the formula for the compound between rubidium and fluorine, it would most likely be:

goldenfox [79]

<u>Answer:</u> The formula of the compound formed between rubidium and fluorine is RbF

<u>Explanation:</u>

Ionic bond is defined as the bond which is formed by complete transfer of electrons from one atom to another atom.

The atom which looses the electron is known as electropositive atom and the atom which gains the electron is known as electronegative atom. This bond is usually formed between a metal and a non-metal.

Rubidium is the 37th element of the periodic table having electronic configuration of $1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^1$

This will loose 1 electron to form $Rb^+$ ion

Fluoride is the 9th element of the periodic table having electronic configuration of $1s^22s^22p^5$

This will gain 1 electron to form $F^-$ ion

To form $RbF$ compound, 1 rubidium ion is needed to neutralize the charge on fluoride ion

The formation of the given compounds is shown in the image below.

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3 years ago