The equivalent of the Newton's second law for rotational motions is:
where
is the net torque acting on the object
is its moment of inertia
is the angular acceleration of the object.
Re-arranging the formula, we get
and since we know the net torque acting on the (vase+potter's wheel) system,
, and its angular acceleration,
, we can calculate the moment of inertia of the system:
Hi!
I think the answer is Brainstem. I hope this helps! :)
Answer:
a) E = 1.06 10⁻¹⁹ J, b) v = 9.78 10⁵ m / s
Explanation:
The physical magnitudes can be given in several units, but in general all must be reduced to the same system in a given exercise, the most used system is the international (SI)
1 eV =q V= 1.6 10⁻¹⁹ J
let's reduce the quantities requested
a) E = 1.0 eV to Joule
E = 1.0 eV (1.6 10⁻¹⁹ J / 1 eV)
E = 1.06 10⁻¹⁹ J
b) the kinetic energy is given by
K = ½ m v²
v = 
the mass of the proton is
m = 1,673 10⁻²⁷ kg
let's reduce the energy to the SI system
E = 5000 ev (1.6 10-19 J / 1 eV) = 8000 10⁻¹⁹ J
let's calculate
v = 
v = 
v = 9.78 10⁵ m / s
The expression for the wave function describing this wave is y(x,t) = 0.02 sin(17.95x + 75.4t - 0.00198).
The angular frequency of a wave is 75.4 rad/s.
<h3>
What is wave function?</h3>
A wave function is a mathematical equation for the motion of the wave.
y(x, t) = A sin(kx + ωt + Φ)
where;
- ω is angular speed
- k is angular wavenumber
- Φ is phase angle
The angular wave number of the wave is calculated as follows;
k = 2π/λ
where;
- λ is the wavelength
- k is the angular wavenumber
k = 2π / 0.35
k = 17.95/m
<h3>Angular speed</h3>
ω = 2πf
ω = 2π(12)
ω = 75.4 rad/s
<h3>Phase angle</h3>
75.4(0.2) sin(Φ) = -0.03
sin(Φ) = -0.001989
Φ = arc sin(-0.001989)
Φ = -0.00198
<h3>Wave function</h3>
y(x,t) = 0.02 sin(17.95x + 75.4t - 0.00198)
Thus, the expression for the wave function describing this wave is y(x,t) = 0.02 sin(17.95x + 75.4t - 0.00198).
Learn more about wave function here: brainly.com/question/22675050
#SPJ4
Answer:
2.83×10⁻¹¹ N.
Explanation:
From the question,
Using
F = qvB....................... Equation 1
Where F = magnetic force acting on the duck, q = charge of the duck, v = velocity of the duck, B = magnetic field of the duck.
Given: q = 6.47×10⁻⁸ C, B = 4.09×10⁻⁵ T, v = 10.7 m/s.
Substitute these values into equation 1
F = 6.47×10⁻⁸×4.09×10⁻⁵×10.7
F = 2.83×10⁻¹¹ N.
Hence the magnetic force acting on the duck is 2.83×10⁻¹¹ N.
