They use Newton to measure force
The range, R, of a projectile based on its angle of projection ∅ and velocity v can be directly calculated by:
R = (v²sin2∅)/g
Let the v of ball 1 be v₁
R₁ = (v₁²sin(2*30))/g
v₂ = 2v₁
R₂ = ((2v₁)²sin(2*30))/g
R₂ = 4[(v₁²sin(2*30))/g]
R₂ = 4R₁
So ratio of d2/d1 = 4
Answer:
![g_{moon}=1.67 [m/s^{2} ]](https://tex.z-dn.net/?f=g_%7Bmoon%7D%3D1.67%20%5Bm%2Fs%5E%7B2%7D%20%5D)
Explanation:
The weight of some mass is defined as the product of mass by gravitational acceleration. In this way using the following formula we can find the weight.

where:
w = weight [N]
m = mass = 0.06 [kg]
g = gravity acceleration = 10 [N/kg]
Therefore:
![w=0.06*10\\w=0.6[N]](https://tex.z-dn.net/?f=w%3D0.06%2A10%5C%5Cw%3D0.6%5BN%5D)
By Hooke's law we know that the force in a spring can be calculated by means of the following expression.

where:
k = spring constant [N/m]
x = deformed distance = 6 [cm] = 0.06 [m]
We can find the spring constant.
![k= F/x\\k=0.6/0.06\\k=10 [N/m]](https://tex.z-dn.net/?f=k%3D%20F%2Fx%5C%5Ck%3D0.6%2F0.06%5C%5Ck%3D10%20%5BN%2Fm%5D)
Since we use the same spring on the moon and the same mass, the constant of the spring does not change, the same goes for the mass.
![F_{moon}=k*0.01\\F = 10*0.01\\F=0.1[N]](https://tex.z-dn.net/?f=F_%7Bmoon%7D%3Dk%2A0.01%5C%5CF%20%3D%2010%2A0.01%5C%5CF%3D0.1%5BN%5D)
Since this force is equal to the weight, we can now determine the gravitational acceleration.
![F=m*g_{moon}\\g=F/m\\g = 0.1/0.06\\g_{moon} = 1.67[m/s^{2} ]](https://tex.z-dn.net/?f=F%3Dm%2Ag_%7Bmoon%7D%5C%5Cg%3DF%2Fm%5C%5Cg%20%3D%200.1%2F0.06%5C%5Cg_%7Bmoon%7D%20%3D%201.67%5Bm%2Fs%5E%7B2%7D%20%5D)
According to law of conservation of momentum... as p=m.v so as velocity v increases the momentum also increases in the direction of motion
Given data
*The given force is F = 583 N
*The given distance is s = 1.5 m
*The given time is t = 2.1 s
The formula for the power it takes for a 583 N student to climb up 1.5 m stairs in 2.1 seconds is given as

Substitute the known values in the above expression as

Hence, the power it takes for a 583 N student to climb up 1.5 m stairs in 2.1 seconds is P = 416.42 W