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koban [17]
3 years ago
5

Two forces, one of 100 ponds and the other 150 pounds act on the same object, at angles of 20°and 60°, respectively, withthe pos

itive x-axis. Find the direction and magnitude of the resultant of these forces.
Physics
1 answer:
soldi70 [24.7K]3 years ago
6 0
<h2>Resultant is 235.54 pounds at an angle 44.16° to X axis.</h2>

Explanation:

Forces are 100 pound and 150 pound and angles with x axis are 20°and 60°.

That is force 1 is 100 pound with x axis at 20°

           F₁ = 100 cos 20 i  +  100 sin 20 j

           F₁ = 93.97 i  +  34.20 j          

That is force 2 is 150 pound with x axis at 60°

           F₂ = 150 cos 60 i  +  150 sin 60 j

           F₂ = 75 i  +  129.90 j  

F₁ +  F₂ =  93.97 i  +  34.20 j + 75 i  +  129.90 j

F₁ +  F₂ =  168.97 i  +  164.10 j

\texttt{Magnitude = }\sqrt{168.97^2+164.10^2}\\\\\texttt{Magnitude = }235.54pounds\\\\\texttt{Angle = }tan^{-1}\left ( \frac{164.10}{168.97}\right )\\\\\texttt{Angle = }44.16^0

Resultant is 235.54 pounds at an angle 44.16° to X axis.

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Help with this question.....​
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Answer:

g_{moon}=1.67 [m/s^{2} ]

Explanation:

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w =m*g\\

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g = gravity acceleration = 10 [N/kg]

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w=0.06*10\\w=0.6[N]

By Hooke's law we know that the force in a spring can be calculated by means of the following expression.

F=W\\F = k*x

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We can find the spring constant.

k= F/x\\k=0.6/0.06\\k=10 [N/m]

Since we use the same spring on the moon and the same mass, the constant of the spring does not change, the same goes for the mass.

F_{moon}=k*0.01\\F = 10*0.01\\F=0.1[N]

Since this force is equal to the weight, we can now determine the gravitational acceleration.

F=m*g_{moon}\\g=F/m\\g = 0.1/0.06\\g_{moon} = 1.67[m/s^{2} ]

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1. Calculate the power it takes for a 583 N student to climb up1.5 m stairs in 2.1 seconds. (find work first!)GivenFormulaSubsti
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Given data

*The given force is F = 583 N

*The given distance is s = 1.5 m

*The given time is t = 2.1 s

The formula for the power it takes for a 583 N student to climb up 1.5 m stairs in 2.1 seconds is given as

P=\frac{F\mathrm{}s}{t}

Substitute the known values in the above expression as

\begin{gathered} P=\frac{(583)(1.5)}{(2.1)} \\ =416.42\text{ W} \end{gathered}

Hence, the power it takes for a 583 N student to climb up 1.5 m stairs in 2.1 seconds is P = 416.42 W

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