Answer:
F = 1618.65[N]
Explanation:
To solve this problem we use the following equation that relates the mass, density and volume of the body to the floating force.
We know that the density of wood is equal to 750 [kg/m^3]
density = m / V
where:
m = mass = 165[kg]
V = volume [m^3]
V = m / density
V = 165 / 750
V = 0.22 [m^3]
The floating force is equal to:
F = density * g * V
F = 750*9.81*0.22
F = 1618.65[N]
Answer:
Explanation:
T₁ = 700 + 273 = 973 k
T₂ = 330 + 273 = 603 k
Theoretical efficiency = T₁ - T₂ / T₁
= (973 - 603) / 973
= .38 OR 38%
Operating efficiency = .79 x 38
= 30.02 %
Heat input Q₁ , Heat output to sink Q₂ , conversion into power = Q₁ - Q₂
given Q₁ - Q₂ = 1.3 x 10⁹ W
efficiency = Q₁ - Q₂ / Q₁
Q₁ - Q₂ / Q₁ = 30.02 / 100
100Q₁ - 100Q₂ = 30.02Q₁
69.98 Q₁ = 100Q₂
Q₁ = 1.429 Q₂
Putting this in the relation
Q₁ - Q₂ = 1.3 x 10⁹ W
1.429Q₂ - Q₂ = 1.3 x 10⁹ W
.429Q₂ = 1.3 x 10⁹
Q₂ = 3.03 x 10⁹W
= 3.03 GW.
Answer:
Magnitude of the Frictional force = (mv₀²)/2x₁
Explanation:
For the frictional force to stop the box, it has to produce the deceleration of the box; thereby being the opposing force to the box's motion.
According to Newton's first law of motion
Frictional force = (mass of the box) × (deceleration experienced by the box)
Let the mass of the box be m
Then,
Frictional force = ma
Then we can obtain the deceleration using the equations of motion
v² = u² + 2ax
u = Initial velocity = v₀ m/s
v = Final velocity = 0 m/s (since the box comes to rest at the end)
x = horizontal distance covered = (x₁ - x₀) = x₁ (since x₀ = 0)
a = ?
v² = u² + 2ax
0 = (v₀)² + 2ax₁
2ax₁ = - v₀²
a = - (v₀²)/(2x₁) (minus sign, because it's a deceleration)
Magnitude of the Frictional force = ma = (mv₀²)/2x₁
Answer:
(A) 421 J energy stored in the capacitor for one flash.
(B) The value of capacitance is 0.0537 F
Explanation:
Given :
(A)
Time 
Average power 
W
From power equation,
So energy in one light is given by,
J
Since efficiency is 95 % so we can write, energy stored in one flash,
J
(B)
From the formula of energy stored in capacitor,
Where 
and 
V
