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3 years ago

9

6. If a bicyclist, with initial velocity of zero, steadily gained speed until reaching a final velocity of 39m/s, how far would

she travel
during the race in the same amount of time)?

1 answer:

Bezzdna [24]3 years ago

7 0

Answer:

175 m

Explanation:

The average velocity for constant acceleration is the average of the beginning and ending velocities. That is (0+39)/2=19.5 m/s. If the bicyclist rides for 9 seconds, the distance traveled is ...

(9 s)(19.5 m/s) = 175.5 m

She would travel 175.5 meters in that time.

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A constant torque of 3 Nm is applied to an unloaded motor at rest at time t = 0. The motor reaches a speed of 1,393 rpm in 4 s.

irakobra [83]

Answer:

The moment of inertia of the motor is 0.0823 Newton-meter-square seconds.

Explanation:

From Newton's Laws of Motion and Principle of Motion of D'Alembert, the net torque of a system ( $\tau$ ), measured in Newton-meters, is:

$\tau = I\cdot \alpha$ (1)

Where:

$I$ - Moment of inertia, measured in Newton-meter-square seconds.

$\alpha$ - Angular acceleration, measured in radians per square second.

If motor have an uniform acceleration, then we can calculate acceleration by this formula:

$\alpha = \frac{\omega - \omega_{o}}{t}$ (2)

Where:

$\omega_{o}$ - Initial angular speed, measured in radians per second.

$\omega$ - Final angular speed, measured in radians per second.

$t$ - Time, measured in seconds.

If we know that $\tau = 3\,N\cdot m$ , $\omega_{o} = 0\,\frac{rad}{s }$ , $\omega = 145.875\,\frac{rad}{s}$ and $t = 4\,s$ , then the moment of inertia of the motor is:

$\alpha = \frac{145.875\,\frac{rad}{s}-0\,\frac{rad}{s}}{4\,s}$

$\alpha = 36.469\,\frac{rad}{s^{2}}$

$I = \frac{\tau}{\alpha}$

$I = \frac{3\,N\cdot m}{36.469\,\frac{rad}{s^{2}} }$

$I = 0.0823\,N\cdot m\cdot s^{2}$

The moment of inertia of the motor is 0.0823 Newton-meter-square seconds.

5 0

3 years ago

Help again please !!!

rusak2 [61]

D I think .... don’t be mad if I’m wrong

5 0

3 years ago

What constant acceleration (in ft/s2) is required to increase the speed of a car from 27 mi/h to 50 mi/h in 5 seconds

SIZIF [17.4K]

Answer:

6.746 ft/s^2

Explanation:

v(t)=50

v(0)=27

t=5/3600 = 1/720 hours

v(t)-v(0)= a(t-0)

50-27= a(1/720)

a= 23*720= 16560 mi/h^2

16560mi/h^2 * 5280/3600^2 (ft/s^2) =6.746 ft/s^2

4 0

3 years ago

Explain each of the following phenomena and how they extend our understanding of genetics from the work done by Gregor Mendel an

Korolek [52]

Answer:

Incomplete Dominance: In this case, the 3rd different phenotype is created by the heterozygous(CwCr) (for example, pink)

Co-Dominance: the heterozygous is observed to show both the homozygous conditions (for example the blood type iAiB shows both A and B carbohydrates)

Multiple alleles: This is when a gene has over 2 alleles (i.e. blood has ia ib i)

Polygenic inheritance: This is when over two different gene leads to the expression of a trait.

Pleiotropy: This is the when a gene shows several effects on an organism.

Epistasis: This is when more than one gene have strong control on the expression of a trait (for example, E/e allele creates pigments)

Sex-linkage: This refers to the genes found in sex chromosomes

Gene Linkage: These are the genes situated in a similar chromosome.

Explanation:

Incomplete Dominance: In this case, the 3rd different phenotype is created by the heterozygous(CwCr) (for example, pink)

Co-Dominance: the heterozygous is observed to show both the homozygous conditions (for example the blood type iAiB shows both A and B carbohydrates)

Multiple alleles: This is when a gene has over 2 alleles (i.e. blood has ia ib i)

Polygenic inheritance: This is when over two different gene leads to the expression of a trait.

Pleiotropy: This is the when a gene shows several effects on an organism.

Epistasis: This is when more than one gene have strong control on the expression of a trait (for example, E/e allele creates pigments)

Sex-linkage: This refers to the genes found in sex chromosomes

Gene Linkage: These are the genes situated in a similar chromosome.

7 0

3 years ago

A geneticist looks through a microscope to determine the phenotype of a fruit fly. The microscope is set to an overall magnifica

grin007 [14]

Answer:

$f_e = 1.51 cm$

Explanation:

given.

magnification(m) = 400 x

focal length (f_0)= 0.6 cm

distance between eyepiece and lens (L)= 16 cm

Near point (N) = 25 cm

focal length of the eyepiece (f_e)= ?

using equation

$m = -\dfrac{L-f_e}{f_o}.\dfrac{N}{f_e}$

$400 = \dfrac{16-f_e}{0.6}.\dfrac{25}{f_e}$

$9.6 = \dfrac{16-f_e}{f_e}$

$9.6f_e = 16-f_e$

$10.6 f_e = 16$

$f_e = 1.51 cm$

3 0

3 years ago