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Nikitich [7]
3 years ago
13

What is the atomic mass of Jupiter?

Physics
1 answer:
lana [24]3 years ago
4 0
The mass of Jupiter is 1.9 x 1027 kg.
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True or false: objects fall toward earth at a rate of 9.8 m/s because of centripetal force.
Citrus2011 [14]
Sadly, no. The statement kind of has some appropriate words in it, but it's badly corrupted. Objects don't fall to Earth at a rate of 9.8 m/s, and the force that accelerates them downward is not a centripetal one.
4 0
3 years ago
A hummingbird flies 1.2 m along a straight path at a height of 3.4 m above the ground. Upon spotting a flower below, the humming
Viefleur [7K]

Answer:1.84

Explanation:

Given

Humming bird travels 1.2 m along a straight line at height of 3.4 m

Now bird drops 1.4 m to hover in front of the flower

So bird net displacement is

displacement=\sqrt{1.2^2+1.4^2}

displacement=\sqrt{3.4}

=1.84

7 0
3 years ago
One billiard ball is shot east at 2.2m/s. A second, identical billiard ball is shot west at 1.2m/s. The balls have a glancing co
Kruka [31]

Answer:

v_{1}=1.886 \frac{m}{s}

β= 57.99 south of east

Explanation:

v_{1}=2.2 \frac{m}{s} \\v_{2}=1.2 \frac{m}{s} \\m_{1}=m_{2}=m\\v_{fx}=1.6 \frac{m}{s} \\v_{fy}=?

Velocity in axis x the two balls come one from east and west

m_{1}*v_{1x}+m_{2}*v_{2x}=m_{1}*v_{fx1}+m_{2}*v_{fx2}\\m*(v_{1x}+v_{2x})=m*(v_{fx1}+v_{fx2})\\v_{fx2}=0\\v_{1x}+v_{2}=v_{f1}+0\\v_{fx1}=2.2 \frac{m}{s}+(1.2\frac{m}{s})\\  v_{fx1}=1 \frac{m}{s} \\

Velocity in axis y initial is zero so:

v_{y1}+v_{y2}=v_{y1f}+v_{y2f}\\v_{y1}=0\\v_{y2}=0\\v_{y1f}+v_{y2f}=0\\v_{y1f}=-v_{y2f}\\v_{y2f}=1.6\frac{m}{s}

v=\sqrt{v_{1fx}^{2}+v_{1fy}^{2}}\\ v=\sqrt{1^{2}+1.6^{2}}\\v=1.886 \frac{m}{s}

Angle is find using:

tan(β)=\frac{v_{fy}}{v_{fx}}

\beta =tan^{-1}*\frac{1.6}{1}=57.99

5 0
4 years ago
Find the average velocity of the car during the time last three second interval. Answer in units of m/s.
Pani-rosa [81]

Answer:

<u>Average Velocity:</u>

When a body covers some displacement moving from point A to B, in a given time,t. Then dividing the total distance covered by the time taken to complete the displacement is called as the average velocity of that car.

We can calculate the average velocity of car by subtracting the initial displacement of a body,s₁ from  the final displacement position of the body, s₂. And then dividing by the initial time,t₁ been subtracted from the final time,t₂.

  • Δv=x₂-x₁/t₂-t₁,

We will get the required results, now if we want to obtain the results in the final three seconds then, we can have the following explanation to that as given.

Explanation:

Lets say, that we have the car moving for 10 seconds and then it stops at the eleventh second of the trip on final position, of the displacement. Then we divide the whole trips into small segments, as we will have the different velocity at each interval but, the velocity is unknown at the last 3 seconds is unknown=?.  

  • Total time taken, Δt= 11 seconds,
  • Then lets say the velocity at the 8th second is , v=25 m/s,then
  • Δv=x₂-(25)/11-0,⇒Δv=x₂-25/11,
3 0
3 years ago
A hockey puck has a momentum of 3.8 kg•m/s [E]. If its
agasfer [191]

Answer:

1.6 \times 10 { }^{ - 1} kg \\

Explanation:

I hope, it helped you.

4 0
3 years ago
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