When you heat water on a stove, how does its energy change?

A 1.2 nf parallel-plate capacitor has an air gap between its plates. Its capacitance increases by 3.0 nf when the gap is filled

Damm [24]

Answer:

2.5

Explanation:

The capacitance of a parallel-plate capacitor filled with dielectric is given by

$C=kC_0$

where

k is the dielectric constant

$C_0$ is the capacitance of the capacitor without dielectric

In this problem,

$C_0=1.2 nF$ is the capacitance of the capacitor in air

$C=3.0 nF$ is the capacitance with the dielectric inserted

Solving the equation for k, we find

$k=\frac{C}{C_0}=\frac{3.0 nF}{1.2 nF}=2.5$

3 0

3 years ago

Read 2 more answers

Come all ruj-jxgn-qua

Shalnov [3]

Answer:

this app is for solving doubts not sending links ok

5 0

3 years ago

In recent years, astronomers have found planets orbiting nearby stars that are quite different from planets in our solar system.

Marizza181 [45]

3.86 m/s^2 is the value of gravity on this large, but low-density, world.

given :

Kepler-12b

diameter= 1.7 times of Jupiter (R_Jupiter = 6.99 × 10^7 m),

mass = 0.43 Jupiter (M_Jupiter = 1.90 × 10^27 kg ).

g = GM/r^2

g = 6.67×10^-11 × 0.43×1.9×10^27/( 1.7×6.99×10^7)^2

g = 3.859 ~ 3.86 m/s^2

Gravity, also referred to as gravitation, is the unchanging force of attraction that binds all matter together in mechanics. It is by far the weakest known force in nature, so it has no effect on determining the internal properties of common matter.

On Earth, everything has weight, or a gravitational pull that is imposed by the planet's mass and proportional to the object's mass. A measure of the force of gravity is the acceleration that freely falling objects experience. At the surface of the Earth, gravity accelerates at a rate of about 9.8 meters per second. As a result, an object's speed increases during free fall by about 9.8 meters per second. At the Moon's surface, a freely falling body accelerates to about 1.6 m/s2.

To know more about gravity visit : brainly.com/question/14428640

#SPJ4

6 0

1 year ago

A charge Q is to be divided into two parts, labeled 'q' and 'Q-q? What is the relationship of q to Q if, at any given distance,

Lisa [10]

Answer:

Explanation:

The two charges are q and Q - q. Let the distance between them is r

Use the formula for coulomb's law for the force between the two charges

$F = \frac{Kq_{1}q_{2}}{r^{2}}$

So, the force between the charges q and Q - q is given by

$F = \frac{K\left ( Q-q \right )q}}{r^{2}}$

For maxima and minima, differentiate the force with respect to q.

$\frac{dF}{dq} = \frac{k}{r^{2}}\times \left ( Q - 2q \right )$

For maxima and minima, the value of dF/dq = 0

So, we get

q = Q /2

Now $\frac{d^{2}F}{dq^{2}} = \frac{-2k}{r^{2}}$

the double derivate is negative, so the force is maxima when q = Q / 2 .

6 0

3 years ago

an air craft is travelling due north with velocity of 100m/s astrong wind blow from the west with in velocity of 25m/s the reshs

OleMash [197]

Explanation:

The aircraft is traveling north at 100 m/s.

The wind blows from the west (towards the east) at 25 m/s.

The two vectors form a right triangle. The magnitude of the resultant velocity can be found with Pythagorean theorem:

v² = vx² + vy²

v² = (25 m/s)² + (100 m/s)²

v = 103 m/s

The direction can be found with trigonometry:

θ = atan(vy / vx)

θ = atan(100 / 25)

θ = 76.0°

The resultant velocity is 103 m/s at 76.0° north of east.

8 0

3 years ago