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mr_godi [17]
3 years ago
11

Jill mixes 4 grams of vanilla extract into the 800 grams of cake batter's he has prepared. What is the concentration of vanilla

in her "solution" of cake batter?
Chemistry
1 answer:
Ivenika [448]3 years ago
8 0

<u>Answer:</u> The concentration of vanilla extract in the solution is 0.50 % (m/m)

<u>Explanation:</u>

We are given:

Mass of vanilla extract (solute) = 4 grams

Mass of cake's batter (solvent) = 800 grams

Mass of solution = Mass of solute + Mass of solvent = 4 + 800 = 804 grams

To calculate the mass percentage (concentration) of vanilla extract in the solution, we use the equation:

\text{Concentration of vanilla extract}=\frac{\text{Mass of vanilla extract}}{\text{Mass of solution}}\times 100

Putting values in above equation, we get:

\text{Concentration of vanilla extract}=\frac{4g}{804g}\times 100\\\\\text{Concentration of vanilla extract}=0.50\%

Hence, the concentration of vanilla extract in the solution is 0.50 % (m/m)

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4 years ago
To which of the third period element does this belong
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Explanation:

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7 0
3 years ago
Read 2 more answers
Gaseous ammonia chemically reacts with oxygen O2 gas to produce nitrogen monoxide gas and water vapor. Calculate the moles of am
mel-nik [20]

Answer:

1.7 moles of ammonia, NH₃.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

4NH₃ + 5O₂ —> 4NO + 6H₂O

From the balanced equation above,

4 moles of NH₃ reacted to produce 4 moles of NO.

Finally, we shall determine the number of mole of ammonia, NH₃, needed to produce 1.7 moles of nitrogen monoxide, NO. This can be obtained as follow:

From the balanced equation above,

4 moles of NH₃ reacted to produce 4 moles of NO.

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5 0
3 years ago
Given the equation: 2H2 + O2 → 2H2O, how many moles of oxygen are needed to react with 13 moles of hydrogen
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Explanation:

2H2 + O2 = 2H2O

2mol. 1mol. 2mol

2mol reacts with 1mol

13mol reacts with x

x=<u>13mol</u><u> </u><u>×</u><u> </u><u>1mol</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>2mol</u>

x= <u>13mol</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>2mol

x= 6.5mol of oxygen

6 0
2 years ago
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