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3 years ago

5 points If you can help me out my doods

Physics

1 answer:

enot [183]3 years ago

6 0

7. solar flare: f.

8. core: h.

9. chromosphere: b.

10. sunspot: d.

11. corona: c.

12. nuclear fusion: j.

13. photosphere: a.

14. solar wind: g.

15. prominence: e.

16. radiation zone: k.

17. convection zone: i.

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4 kg of water was

morpeh [17]

Given :

Mass =5kg

=20

∘

C,T

=100

∘

ΔT=100−20=80

∘

Q=m×C×ΔT

where C= specific heat capacity of water

=4200J/(kgK)

Q=5×4200×80

=1680000 Joule.

=1680KJ

6 0

3 years ago

Which of the following would most likely happen if water did not form hydrogen bonds?

Trava [24]

Option C is the correct answer

6 0

4 years ago

Answer attachment below

polet [3.4K]

Answer:

second option is the answer.

6 0

3 years ago

Calculate the energy released by the electron-capture decay of 5727Co. Consider only the energy of the nuclei (ignore the energy

erma4kov [3.2K]

Answer:

Explanation:

⁵⁷Co₂₇ + e⁻¹ = ²⁷Fe₂₆

mass defect = 56.936296 + .00055 - 56.935399

= .001447 u

equivalent energy

= 931.5 x .001447 MeV

= 1.3479 MeV .

= 1.35 MeV

energy of gamma ray photons = .14 + .017

= .157 MeV .

Rest of the energy goes to neutrino .

energy going to neutrino .

= 1.35 - .157

= 1.193 MeV.

5 0

3 years ago

A 0.600 m long pendulum is used to determine the acceleration due to gravity on a distant plane. If 20 oscillations are complete

katrin2010 [14]

Answer:

7.50 m/s^2

Explanation:

The period of a pendulum is given by:

$T=2\pi \sqrt{\frac{L}{g}}$ (1)

where

L = 0.600 m is the length of the pendulum

g = ? is the acceleration due to gravity

In this problem, we can find the period T. In fact, the frequency is equal to the number of oscillations per second, so:

$f=\frac{N}{t}=\frac{20}{35.5 s}=0.563 Hz$

And the period is the reciprocal of the frequency:

$T=\frac{1}{f}=\frac{1}{0.563 Hz}=1.776 s$

And by using this into eq.(1), we can find the value of g:

$g=\frac{4 \pi^2 L}{T^2}=\frac{4 \pi^2 (0.600 m)}{(1.776 s)^2}=7.50 m/s^2$

6 0

3 years ago