Question

HELP! 16x^(2)-40x+6x-15=0 I already factored and this is the extended version, but I don't know where to go from here. Show your work :)

Answer 1

If you're trying to solve for x, you need to use the quadratic formula.  
$\frac{-b+/- \sqrt{b^2 - 4(a)(c)} }{2a}$  
Plug in the numbers from the standard form of a quadratic equation  
(which is $ax^2 + bx + c = 0$)   
$\frac{34+/- \sqrt{34^2 - 4(16)(15)} }{2(16)}$  
From here, this solves down to  
$\frac{34+/- \sqrt{196}}{32}$  
Take the square root of 196, which is 14  
$\frac{34+/- 14}{32}$  
Now, you can solve for both the + and - variations on the equation.  
The solutions to your equation are 1.5 and 5/8 (probably)