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Sedbober [7]
3 years ago
10

7. A Candle is placed 4 cm in front of a convex lens. The image of the candle is focused on a sheet of paper that is exactly 10

cm behind the lens
What is the Magnification of the image​
Physics
1 answer:
velikii [3]3 years ago
3 0

Answer:

Magnification m is 2.5cm

Explanation:

This problem bothers on lenses

Given data

Object distance u= 4cm

Height of object v= 10 cm

The problem is quite straightforward seeing that object and image distances are given

We know that the magnification

m= size of image/size of object

m= v/u= 10/4 = 2. 5cm

What is a convex lens

A convex lens is a type of lens that has the centre thicker than the ends, the thickness at the centre makes the lens surface to curve outward. Convex lens causes close light rays of light to converge at a point after refraction.

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Find the current if 55 C of charge pass a particular point in a circuit in 5 seconds.
uranmaximum [27]

Answer:

<em>The current is 11 Amperes</em>

Explanation:

<u>Electric Current</u>

The electric current is defined as a stream of charged particles that move through a conductive path.

The current intensity can be calculated as:

\displaystyle I=\frac{Q}{t}

Where:

Q = Electric charge

t   = Time taken by the charge to move through the conductor

The current intensity is often measured in Amperes.

The charge passing through a point in a circuit is Q= 55 c during t=5 seconds, thus the current intensity is:

\displaystyle I=\frac{55}{5}

I = 11 Amp

The current is 11 Amperes

4 0
3 years ago
A wheel is rotating freely at angular speed 420 rev/min on a shaft whose rotational inertia is negligible. A second wheel, initi
Mashcka [7]

Answer:60 rev/min

Explanation:

Given

angular speed of first shaft \omega _1=420\ rev/min

Moment of inertia of second shaft is seven times times the rotational speed of the first i.e. If I is the moment  of inertia of first wheel so moment of inertia of second is 7 I

As there is no external torque therefore angular momentum is conserved

L_1=L_2

I_1\omega _1=I_2\omega _2

I\times (420)=7 I\times (\omega _2)

\omega _2=\frac{420}{7}

\omega _2=60\ rev/min  

8 0
3 years ago
A=vf-vi/t is the equation for calculating the acceleration of an object. write out the relationship shown in the equation using
Lelechka [254]
Basically it is the difference in velocity divided by the time it takes to make that change.
3 0
3 years ago
13) How much mechanical energy does a swinging bowling ball have if it has 250J of kinetic energy and
Musya8 [376]

Answer: what does a,b,c stand for?

Explanation:

5 0
2 years ago
Read 2 more answers
hich of the following statements are true for magnetic force acting on a current-carrying wire in a uniform magnetic field?Check
leonid [27]

Explanation:

The magnetic force acting on a current carrying wire in a uniform magnetic field is given by :

F=I(L\times B)

or

F=ILB\ sin\theta

Where

\theta is the angle between length and the magnetic field

The magnetic force is perpendicular to both current and magnetic field. It is maximum when it is perpendicular to both current and magnetic field.

So, the correct options are :

  1. The magnetic force on the current-carrying wire is strongest when the current is perpendicular to the magnetic field lines.
  2. .The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the field.
  3. The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the current.
7 0
3 years ago
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