Answer: The answer is B, The variable that should go on the x- axis is the temperature of water.
Explanation: In an experiment, we must have two variables; the independent variable and the dependent variable.
If the results of the experiment is reported in graphical format, the independent variable is plotted on the x axis while the dependent variable is plotted on the y axis.
In this case, the independent variable is the temperature of the water while the dependent variable is the mass of salt dissolved in 100 mL of water.
Therefore, the variable that should go on the x- axis is the temperature of water.
Yes, that’s true it has electrical energy
Answer:
Explanation:
A vector is parallel to the y axis .
Let its magnitude be A . So the vector can be represented as A j .
where i and j are unit vectors in x and y axis direction .
The x component of A j will be dot product of A j with i
The x component of A j = A j . i
= A x 0 [ Since j . i = 0 ]
= 0
Answer:
(B) The total internal energy of the helium is 4888.6 Joules
(C) The total work done by the helium is 2959.25 Joules
(D) The final volume of the helium is 0.066 cubic meter
Explanation:
(B) ∆U = P(V2 - V1)
From ideal gas equation, PV = nRT
T1 = 21°C = 294K, V1 = 0.033m^3, n = 2moles, V2 = 2× 0.033=0.066m^3
P = nRT ÷ V = (2×8.314×294) ÷ 0.033 = 148140.4 Pascal
∆U = 148140.4(0.066 - 0.033) = 4888.6 Joules
(C) P2 = P1(V1÷V2)^1.4 =148140.4(0.033÷0.066)^1.4= 148140.4×0.379=56134.7 Pascal
Assuming a closed system
(C) Wc = (P1V1 - P2V2) ÷ 0.4 = (148140.4×0.033 - 56134.7×0.066) ÷ 0.4 = (4888.6 - 3704.9) ÷ 0.4 = 1183.7 ÷ 0.4 = 2959.25 Joules
(C) Final volume = 2×initial volume = 2×0.033= 0.066 cubic meter