Option (a) is correct.
Falling objects accelerate as they approach the ground.This is because of the force of gravity acting on the falling objects. so the velocity of these objects increases continuously as they approach the ground. the acceleration acting on the falling objects is a constant ( close to the surface of earth) and is called as acceleration due to gravity denoted by g. value of g=9.8 m/s².
Answer:
V = 9.682 × 10^(-6) V
Explanation:
Given data
thick = 190 µm
wide = 4.20 mm
magnitude B = 0.78 T
current i = 32 A
to find out
Calculate V
solution
we know v formula that is
V = magnitude× current / (no of charge carriers ×thickness × e
here we know that number of charge carriers/unit volume for copper = 8.47 x 10^28 electrons/m³
so put all value we get
V = magnitude× current / (no of charge carriers ×thickness × e
V = 0.78 × 32 / (8.47 x 10^28 × 190 × 1.602 x 10^(-19)
V = 9.682 × 10^(-6) V
Answer:
Explanation:
By energy conservation we know that spring energy is converted into kinetic energy of the block
so we will have
so we will have
now we will have same thing for another mass 4m which moves out with speed 5v
so we have
now from above two equations we have
so we have
Answer:
Earth's atmosphere is a layer of gases surrounding the planet Earth and retained by the Earth's gravity. It contains roughly 78% nitrogen and 21% oxygen 0.97% argon and carbon dioxide 0.04% trace amounts of other gases, and water vapor. This mixture of gases is commonly known as air. Explanation:
Sn is in group 4 so has 4 electrons in the outer shell (draw<span> these as dots) Add 1 more electron from each bond to F (+6) </span>
