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dmitriy555 [2]
3 years ago
6

Select the circle containing inaccurate information that does not align with the big bang theory.

Physics
2 answers:
Fofino [41]3 years ago
6 0
It's the second to last one
-Dominant- [34]3 years ago
4 0

The Big Bang: 0 to 10-43 Seconds

The universe popped into existence and began expanding from a single, infinitely small, infinitely hot, and infinitely dense point. Before this moment, neither time nor space existed. For this reason, it is meaningless to ask what happened before the big bang. This question would be similar to asking what is north of the North Pole.

It is the first one...Only space existed.  

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Can some one do for me a power point
mash [69]

Answer:

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Explanation:

hope this helps❤️

4 0
3 years ago
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Where are the colored circles place a text box near the circle​
laila [671]
What? Do you have a picture of the problem ?
4 0
3 years ago
A tin can has a radius of 0.0410m and is 185 m high if the air is removed from inside the can how much forces will the outside a
grin007 [14]

The force exerted on the bottle is 532 N

Explanation:

When the air is removed from inside the bottle, vacuum is created, therefore the external pressure (the atmospheric pressure) is no longer balanced, and it creates a net force downward on the can.

The pressure is related to the force by the equation:

p=\frac{F}{A}

where

p is the pressure

F is the force

A is the area of the can

Here we have:

p=1.01\cdot 10^5 Pa is the atmospheric pressure

r = 0.0410 m is the radius of the can, so the area is

A=\pi r^2 = \pi (0.0410)^2=5.27\cdot 10^{-3}m^2

And solving for F, we can find the force on the can:

F=pA=(1.01\cdot 10^5)(5.27\cdot 10^{-3})=532 N

Learn more about pressure:

brainly.com/question/4868239

brainly.com/question/2438000

#LearnwithBrainly

3 0
4 years ago
The fundamental frequency of a guitar string is 367 hz . part a what is the fundamental frequency if the tension in the string i
ANTONII [103]
The fundamental frequency of a string is given by:
f_1 =  \frac{1}{2L} \sqrt{ \frac{T}{\mu} }
where L is the string's length, T the tension and \mu the linear density of the string.

We can see that f1 is proportional to the square root of T: \sqrt{T}.
This means that if the new tension is half the initial value, the new fundamental frequency will be proportional to \sqrt{ \frac{T}{2} }= \frac{ \sqrt{T} }{ \sqrt{2} }=  \frac{f_1}{ \sqrt{2} }

So, the new fundamental frequency will be
f_1 ' =  \frac{367 Hz}{ \sqrt{2} }=259.5 Hz
6 0
4 years ago
Work is done when force is applied ____________________________________________?
monitta

Answer:

D none of the above

Explanation:

mark me brainlyest pls?

6 0
3 years ago
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