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4 years ago

How many moles of MgO are produced when .250 mol of Mg reacts completely with O2

Chemistry

1 answer:

artcher [175]4 years ago

7 0

Answer:

0.250 mol

Explanation:

The reaction between Mg and O2 is given by;

2Mg + O2 --> 2MgO

From the equation above; 2 moles of Mg reacts to form 2 moles of MgO.

0.250 mol of Mg would produce x mol of MgO.

2 = 2

0.250 = x

x = 0.250 * 2/2 = 0.250 mol

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¿Cómo se llama el proceso en donde se transforma el oxígeno en dióxido de carbono

Ierofanga [76]

Answer:

respiración

Explanation:

8 0

3 years ago

Calculate the equilibrium concentration of H 3 O H3O in a 0.20 M M solution of oxalic acid. Express your answer to two significa

Black_prince [1.1K]

Answer: The equilibrium concentration of $H_3O^+$ ion is $8.3064\times 10^{-2}M$

Explanation:

We are given:

Molarity of oxalic acid solution = 0.20 M

Oxalic acid $(H_2C_2O_4)$ is a weak acid and will dissociate 2 hydrogen ions.

The chemical equation for the first dissociation of oxalic acid follows:

$H_2C_2O_4(aq.)+H_2O\rightleftharpoons H_3O^+(aq.)+HC_2O_4^-(aq.)$

Initial: 0.20

At eqllm: 0.20-x x x

The expression of first equilibrium constant equation follows:

$Ka_1=\frac{[H_3O^+][HC_2O_4^{-}]}{[H_2C_2O_4]}$

We know that:

$Ka_1\text{ for }H_2C_2O_4=0.059$

Putting values in above equation, we get:

$0.059=\frac{x\times x}{(0.20-x)}\\\\x=-0.142,0.083$

Neglecting the negative value of 'x', because concentration cannot be negative.

So, equilibrium concentration of hydronium ion = x = 0.083 M

The chemical equation for the second dissociation of oxalic acid:

$HC_2O_4^-(aq.)+H_2O\rightarrow H_3O^+(aq.)+C_2O_4^{2-}(aq.)$

Initial: 0.083

At eqllm: 0.083-y 0.083+y y

The expression of second equilibrium constant equation follows:

$Ka_2=\frac{[H_3O^+][C_2O_4^{2-}]}{[HC_2O_4^-]}$

We know that:

$Ka_2\text{ for }H_2C_2O_4=6.4\times 10^{-5}$

Putting values in above equation, we get:

$6.4\times 10^{-5}=\frac{(0.083+y)\times y}{(0.083-y)}\\\\y=-0.083,0.0000639$

Neglecting the negative value of 'x', because concentration cannot be negative.

So, equilibrium concentration of hydronium ion = y = 0.0000639 M

Total concentration of hydronium ion = [x + y] = [0.083 + 0.0000639] = 0.0830639 M

Hence, the equilibrium concentration of $H_3O^+$ ion is $8.3064\times 10^{-2}M$

7 0

3 years ago

If an automobile air bag has a volume of 11.6 ll , what mass of nan3nan3 (in gg ) is required to fully inflate the air bag upon

Tresset [83]

22.3 g of NaN₃ are required to fully inflate an airbag of 11.6 L at STP.

To find the mass, the given data was,

Volume = 11.6 Liters

<h3>What is decomposition reaction?</h3>

A decomposition reaction can be defined as a chemical reaction in which one reactant breaks down into two or more products.

In airbags, sodium azide decomposes to form sodium and nitrogen gas, which inflates the bag. The decomposition reaction is:

2 NaN₃ ⇒ 2 Na + 3 N₂

We can calculate the mass of NaN₃ needed to produce 11.6 L of N₂ at STP, using the following relations.

At STP, 1 mole of N₂ occupies 22.4 L.
The molar ratio of N₂ to NaN₃ is 3:2.
The molar mass of NaN₃ is 65.01 g/mol.

Substituting all the known values to find the volume,

11.6 × ( 1 / 22.4) × ( 2/3) × ( 65.01 / 1)

= 22.4 g.

22.4 g of NaN₃ are required to fully inflate an airbag of 11.6 L at STP.

Learn more about decomposition reaction,

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2 years ago

The balanced chemical equation for the combustion of methane is: CH4(g) + 2 O2(g) → CO2(g) + 2 H2O(g) Which of the following sta

Jobisdone [24]

Answer:

Option 2. One mole of methane gas reacts with two moles of dioxygen gas, producing one mole of carbon dioxide gas and two moles of gaseous water.

Explanation:

The clue is in the stoichiometry of the reaction:

1 CH₄(g) + 2 O₂(g) → 1 CO₂(g) + 2 H₂O(g)

In any chemistry reaction, the stoichiometric coefficients are moles; moles of reactants to produce moles of products

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4 years ago

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3 years ago