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liberstina [14]
4 years ago
7

How many moles of MgO are produced when .250 mol of Mg reacts completely with O2

Chemistry
1 answer:
artcher [175]4 years ago
7 0

Answer:

0.250 mol

Explanation:

The reaction between Mg and O2 is given by;

2Mg + O2 --> 2MgO

From the equation above; 2 moles of Mg reacts to form 2 moles of MgO.

0.250 mol of Mg would produce x mol of MgO.

2 = 2

0.250 = x

x = 0.250 * 2/2 = 0.250 mol

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3 years ago
What volume would 0.735 moles of O2 gas occupy at STP
tatiyna

Answer:

16.5 dm³

Explanation:

Data Given:

no. moles of O₂ =  0.735 moles

volume of O₂ = ?

Solution:

Now

we have to find volume of O₂ gas

Formula used for this purpose

                   No. of moles = Volume / molar volume

where

molar volume at STP for Oxygen (O₂) = 22.4 dm³/mol

              No. of moles O₂ = Volume of O₂ / 22.4 dm³/mol . . . . . .(1)

Put values in equation 1

                0.735 = Volume of O₂ / 22.4 dm³/ mol

rearrange above equation

              Volume of O₂ = 0.735 x 22.4 dm³/ mol

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So,

the volume of O₂ at STP is 16.5 dm³

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