When you are ice skating, to get started, you push your skate backwards on the ice and, as a result, begin to move forward. Whic
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Student 1 would have a power 467 W and student 2 would have a power of 433 W. The correct option is the fourth option - Student 1 would have 467 W, and Student 2 would have 433 W of power.
From the question,
We are to calculate the power each student would have to climb the flight of stairs.
Power can be calculated using the formula
Where
P is Power
F is the force
d is the distance
and t is the time
NOTE: The weight of the students represent the force
- For student 1
F = 700 N
d = 4 m
t = 6 s
∴
P = 467 W
- For student 2
F = 650 N
d = 4 m
t = 6 s
∴
P = 433 W
Hence, Student 1 would have a power 467 W and student 2 would have a power of 433 W. The correct option is the fourth option - Student 1 would have 467 W, and Student 2 would have 433 W of power.
Learn more here: brainly.com/question/18801566
Answer:
6.5 x 10^32 eV
Explanation:
mass of particle, mo = 1 g = 0.001 kg
velocity of particle, v = half of velocity of light = c / 2
c = 3 x 10^8 m/s
Energy associated to the particle
E = γ mo c^2
Convert Joule into eV
1 eV = 1.6 x 10^-19 J
So,