Answer:
A
Explanation:
the metal lunchbox has a higher conductivity
<h2 />
Common examples include the reflection of light, sound and water waves. The law of reflection says that for specular reflection the angle at which the wave is incident on the surface equals the angle at which it is reflected. Mirrors exhibit specular reflection.
Initially there were 10 bulbs of 60 Watt power
So total power of all bulbs = 60 * 10 = 600 W
now each bulb used for 4 hours daily
so total energy consumed daily



now we have total power consumed in 1 year

cost of electricity = 10 cents/ kWh
so total cost of energy for one year

Now if all 60 Watt bulbs are replaced by 30 Watt bulbs
So total power of all bulbs = 30 * 10 = 300 W
now each bulb used for 4 hours daily
so total energy consumed daily



now we have total power consumed in 1 year

cost of electricity = 10 cents/ kWh
so total cost of energy for one year

total money saved in 1 year

The resistance (R) of the circuit is 707.1 ohms and the inductance (L) is 0.032 H.
<h3>Resistance of the circuit</h3>
For the phase constant of 45⁰, impedance is equal to the resistance of the circuit.

<h3>Resonant frequency</h3>

<h3>At driven frequency</h3>

<em>solve 1 and 2 together</em>

Learn more about impedance of RLC circuit here: brainly.com/question/372577