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3 years ago

Can two or more elements be combined chemically to make a new element? Explain your answer.

2 answers:

6 0

Yes; this process if called nuclear fusion, and an example of it is in the sun. Elements in the sun are combined to create heavier elements in order to provide fuel.

Likurg_2 [28]3 years ago

6 0

Answer:

I think it's quite simple.

Explanation:

An element is basically a group of similar atoms combined. For example, gold atoms combine to form a gold element (metal).
A compound is the product of the chemical combination of two or more atoms. For example, two Hydrogen atoms and an Oxygen atom combine to form water (a compound).
And a mixture is the product of the physical combination of two or more substances (not chemically combined). For example mixing water and milk powder. I hope it was helpful.

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Using ethanol and sodium or potassium cyanide as the sources of the carbon atoms, along with any necessary inorganic reagents, s

11Alexandr11 [23.1K]

Answer:

Please see attachment

Explanation:

Please see attachment

3 0

3 years ago

1‑Propanol ( P⁰ 1 = 20.9 Torr at 25 ⁰C ) and 2‑propanol ( P⁰ 2 = 45.2 Torr at 25 ⁰C ) form ideal solutions in all proportions. L

anastassius [24]

Answer : The mole fraction of vapor phase 1‑Propanol and 2‑Propanol is, 0.352 and 0.648 respectively.

Explanation : Given,

Vapor presume of 1‑Propanol $(P^o_1)$ = 20.9 torr

Vapor presume of 2‑Propanol $(P^o_2)$ = 45.2 torr

Mole fraction of 1‑Propanol $(x_1)$ = 0.540

Mole fraction of 2‑Propanol $(x_2)$ = 1-0.540 = 0.46

First we have to calculate the partial pressure of 1‑Propanol and 2‑Propanol.

$p_1=x_1\times p^o_1$

where,

$p_1$ = partial vapor pressure of 1‑Propanol

$p^o_1$ = vapor pressure of pure substance 1‑Propanol

$x_1$ = mole fraction of 1‑Propanol

$p_1=(0.540)\times (20.9torr)=11.3torr$

and,

$p_2=x_2\times p^o_2$

where,

$p_2$ = partial vapor pressure of 2‑Propanol

$p^o_2$ = vapor pressure of pure substance 2‑Propanol

$x_2$ = mole fraction of 2‑Propanol

$p_2=(0.46)\times (45.2torr)=20.8torr$

Thus, total pressure = 11.3 + 20.8 = 32.1 torr

Now we have to calculate the mole fraction of vapor phase 1‑Propanol and 2‑Propanol.

$\text{Mole fraction of 1-Propanol}=\frac{\text{Partial pressure of 1-Propanol}}{\text{Total pressure}}=\frac{11.3}{32.1}=0.352$

and,

$\text{Mole fraction of 2-Propanol}=\frac{\text{Partial pressure of 2-Propanol}}{\text{Total pressure}}=\frac{20.8}{32.1}=0.648$

Thus, the mole fraction of vapor phase 1‑Propanol and 2‑Propanol is, 0.352 and 0.648 respectively.

3 0

3 years ago

I NEED HELP ANSWERING THESE QUESTIONS FOR 50 POINTS!!!!!

Semmy [17]

The answers are true, true, false, true, and false.

7 0

3 years ago

Read 2 more answers

A hiker has packed a bag of chips as a snack. At the start of the hike the pressure was 1.5 atm and the temperature was 35*C. At

Mazyrski [523]

According to <span>Gay-Lussac's Law the temperature and Pressure are directly proportional to each other if the amount and volume of given gas are kept constant.
Mathematically for initial and final states it is expressed as,

P</span>₁ / T₁ = P₂ / T₂ ----- (1)
Data Given;
P₁ = 1.5 atm

T₁ = 35 °C + 273 = 308 K

P₂ = ?

T₂ = 0 °C + 273 = 273 K

Solving Eq. 1 for P₂,

P₂ = P₁ T₂ / T₁

Putting values,
P₂ = (1.5 atm × 273 K) ÷ 308 K

P₂ = 1.32 atm
Result:
As the temperature is decreased so the pressure also decreases from 1.5 atm to 1.32 atm. Therefore the bag will contract.

5 0

3 years ago

How many moles of hcl are required to neutralize aqueous solutions of these bases? 0.03 mol koh?

oksano4ka [1.4K]

The moles of HCl are required to neutralized aqueous solution of the 0.03 KoH

KOH + HCl = KCl + H2O

by use mole ratio between KOH to HCl which is 1:1 the moles Of HCl is also 0.03 moles

5 0

3 years ago