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3 years ago

What is the most likely radiological device that a terrorist might use in a Weapons of Mass Destruction (WMD) incident?

Physics

1 answer:

zavuch27 [327]3 years ago

7 0

Answer:Radiologic Dispersal Devices (RDD)

Explanation:

Radiologic Dispersal Device (RDD) is commonly known as dirty bomb. These devices require little more skill than is needed to make a conventional bomb and their components are easier to acquire. RDDs utilize conventional explosives to disperse a radioactive material packaged in the device, as opposed to a nuclear device, which creates radiation with its explosion.

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When an object of mass m1 is hung on a vertical spring and set into vertical simple harmonic motion, it oscillates at a frequenc

Arlecino [84]

Answer:

$m_2/m_1=9.745$

The ratio m_2/m_1 of the masses is 9.745

Explanation:

Formula for frequency when mass m_1 is hung on the spring:

$f_1=\frac{1}{2\pi}\sqrt{\frac{k}{m_1}}$

where:

k is the spring constant

Formula for frequency when mass m_2 is hung on the spring along with m_1:

$f_2=\frac{1}{2\pi}\sqrt{\frac{k}{m_1+m_2}}$

where:

k is the spring constant.

In order to find ratio m_2/m_1, Divide the above equations:

$\frac{f_1}{f_2} =\frac{ \frac{1}{2\pi}\sqrt{\frac{k}{m_1}}}{\frac{1}{2\pi}\sqrt{\frac{k}{m_1+m_2}}}$

On Solving the above equation:

$\frac{f_1}{f_2} =\frac{\sqrt{\frac{k}{m_1}}}{\sqrt{\frac{k}{m_1+m_2}}}\\(\frac{f_1}{f_2})^{2} =\frac{m_1+m_2}{m_1} \\(\frac{11.8}{3.60})^2= \frac{m_1+m_2}{m_1} \\10.745=\frac{m_1+m_2}{m_1}\\10.745m_1=m_1+m_2\\m_2=10.745m_1-1m_1\\m_2/m_1=9.745$

The ratio m_2/m_1 of the masses is 9.745

8 0

4 years ago

If you push against a stationary brick wall for several minutes, you do no work

bazaltina [42]

B because in science work means moving an object over a distance

5 0

3 years ago

If an X-ray beam of wavelength 1.4 × 10-10 m makes an angle of 30° with a set of planes in a crystal causing first order constru

kkurt [141]

Answer:

Plane spacing, $d=1.4\times 10^{-10}\ m$

Explanation:

It is given that,

Wavelength of x-ray, $\lambda=1.4\times 10^{-10}\ m$

Angle the x-ray made with a set of planes in a crystal causing first order constructive interference is 30 degrees

We need to find the plane spacing. It is based on Bragg's law such that,

$2d\sin\theta=n\lambda$

d is plane spacing

n = 1 here

$d=\dfrac{\lambda}{2\sin\theta}\\\\d=\dfrac{1.4\times 10^{-10}}{2\times \sin (30)}\\\\d=1.4\times 10^{-10}\ m$

So, the plane spacing is $1.4\times 10^{-10}\ m$ .

5 0

4 years ago

Not understanding this, please help out

allsm [11]

Answer:

greater than

Explanation:

the answer is greater than

3 0

3 years ago

11 Design Imagine that a scientistdiscovered a way to make africtionless surface. What wouldbe some useful applications forthis

m_a_m_a [10]

Answer:

You could move something across the Earth with a little push. It would make fuel really efficient on those pathways. You could make a floor that is impossible to walk on. Everybody would just fall without traction.

Explanation:

3 0

3 years ago