The time required for one wing beat is 5 milliseconds.
<em><u>Explanation</u></em>
Lets assume, the time required for one wing beat is 
seconds
So, the time required for 200 wing beat 
seconds
Given that, the honeybee flaps its wings 200 times per 1 second. So...
So, the time required for one wing beat is 5 milliseconds.
Multiply 10 times 5 then divide it by 4
Y=-2x+-3 I haven't't done this in a long time, sorry. I do remember wanting to k**l myself because this always happened to me when I did remember this stuff
Answer:
The equation is 3n + 13 = 40 The triplets are 9 years old
Step-by-step explanation:
Answer:
366cm²
Step-by-step explanation:
