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Juliette [100K]
3 years ago
13

Check the correctness of formula t=2π √m/k, dimensionally​

Physics
1 answer:
pantera1 [17]3 years ago
4 0

Hi there! Lets see!

  • m is mass, and its units are kg
  • k is the elastic constant measured in newtons per meter (N/m), or kilograms per second squared kg/s²

Therefore:

\sqrt{\dfrac{m}{k}} =\sqrt{\dfrac{[kg]}{[\dfrac{kg}{s^2}]}}  =\sqrt{\dfrac{[kg]}{[kg]}\cdot s^2} = \sqrt{[s]^2} = s

The period is given in seconds so the formula is dimensionally​ correct.

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4 years ago
Different velocity-time graph lines are shown, displaying the behavior of multiple race carts along a linear track.
Studentka2010 [4]

B) Moving with zero acceleration.

Explanation:

Acceleration is defined as the rate of change of the velocity per unit time:

a=\frac{\Delta v}{\Delta t}

In a velocity-time graph, this ratio corresponds to the slope of the curve. In fact:

\Delta v (change in velocity) corresponds to the increase in the y-axis

\Delta t (change in time) corresponds to the increase in the x-axis

So, acceleration corresponds to the slope of the curve in a velocity-time graph. For cart C, the slope is zero, therefore the acceleration is also zero.

8 0
3 years ago
Read 2 more answers
If the particles are oxygen ions carrying a charge of −2e and the magnetic field magnitude is 0.12 T , how long does it take eac
Natali5045456 [20]

Time taken by each ion to travel the semicircular path through the magnetic field is 34 X 10⁻²⁶s.

<u>Explanation:</u>

Given:

Charge of oxygen ion, q = -2

Magnetic Field, B = 0.12 T

Mass of O₂ , m= 2.6 X 10⁻²⁶ Kg

Time, T = ?

We know,

                T = \frac{2\pi m}{qB}

Therefore,

T = 2 X 3.14 X 2.6 X 10⁻²⁶/ 2 X 0.12

T = 68 X 10⁻²⁶s

For semicircular orbit, Time taken would be T/2

T ₓ = 68 X 10⁻²⁶/2 s

T ₓ = 34 X 10⁻²⁶s

Therefore, time taken by each ion to travel the semicircular path through the magnetic field is 34 X 10⁻²⁶s.

4 0
3 years ago
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insens350 [35]

Answer:

Explanation:

a ) x ( t ) = t³ / 3 - t² + t

v = dx / dt = 3 t² / 3 - 2 t + 1 = t² -  2 t + 1

b ) lizard is at rest , v( t ) = 0

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t = 1

c )

velocity is positive when

t² -  2 t + 1  > 0

( t - 1 ) ² > 0

Here we see that LHS is a square so it is always positive whatever be the value of t

So velocity is always positive or lizard is always moving in positive x direction .

d ) It never moves in negative x direction .

e )

a ( t ) = dv / dt = 2t - 2

t = 1

so it has zero acceleration at t = 0 .

7 0
3 years ago
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