1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Juliette [100K]
3 years ago
13

Check the correctness of formula t=2π √m/k, dimensionally​

Physics
1 answer:
pantera1 [17]3 years ago
4 0

Hi there! Lets see!

  • m is mass, and its units are kg
  • k is the elastic constant measured in newtons per meter (N/m), or kilograms per second squared kg/s²

Therefore:

\sqrt{\dfrac{m}{k}} =\sqrt{\dfrac{[kg]}{[\dfrac{kg}{s^2}]}}  =\sqrt{\dfrac{[kg]}{[kg]}\cdot s^2} = \sqrt{[s]^2} = s

The period is given in seconds so the formula is dimensionally​ correct.

You might be interested in
g An astronaut must journey to a distant planet, which is 189 light-years from Earth. What speed will be necessary if the astron
Butoxors [25]

Answer:

The value is v  =  2.999 *10^{8} \  m/s

Explanation:

From the question we are told that

   The time taken to travel to the planet from earth is t = 189 \ light-years

    The  time to be spent on the ship is  t_{s} =  12 \  years

Generally speed can be obtained using the mathematical relation represented below

       t_s  =  2 * t *  \sqrt{1 -  \frac{v^2}{c^2 } }

The 2 in the equation show that the trip is a round trip i.e going and coming back

=>    12 =  2 * 189 *  \sqrt{1 -  \frac{v^2}{(3.0*10^{8})^2 } }

=>     v  =  2.999 *10^{8} \  m/s

5 0
3 years ago
What is the attractive force between all matter in the universe?
kvv77 [185]
The attractive force between all matter in the universe is gravity.
4 0
3 years ago
Read 2 more answers
2. What is the speed of section A? Section B? Section C?
Nutka1998 [239]
Im pretty sure A-10 b-0 c-40
8 0
3 years ago
A simple pendulum is 1.15 meters long and has a period of 6.29 seconds. The pendulum is on an unknown planet. What is the accele
Nastasia [14]

Answer:

The value of the acceleration of gravity of the Unknown Planet = 1.14 \frac{m}{s^{2} }

Explanation:

length of the pendulum (L)= 1.15 m

Time period (T)= 6.29 seconds

We know that time period  of a simple pendulum is given by

⇒ T = 2\pi × \sqrt\frac{L}{g}

put the values in the above formula we get

⇒ T = 2\pi × \sqrt \frac{1.15}{g}

⇒ 6.29 = 2\pi × \sqrt \frac{1.15}{g}

By solving the above equation we get

⇒ g = 1.14 \frac{m}{s^{2} }

This is the value of the acceleration of gravity of the Unknown Planet.

7 0
4 years ago
Which of the following objects is an example of a luminous source?
Korvikt [17]

Answer:

B. Moon

Explanation:

In physics, that would be the answer.

7 0
3 years ago
Read 2 more answers
Other questions:
  • An object is attached to a vertical spring and bobs up and down between points a and
    13·1 answer
  • When matter changes from one state to another, what do we call this process? A. a physical change B. a nuclear change C. an expl
    14·2 answers
  • In concept simulation 10.2 you can explore the concepts that are important in this problem. astronauts on a distant planet set u
    14·1 answer
  • if the accepted thickness of aluminum foil is 1.5x10^5 is your answer percise, accurate or both. explain your answer
    6·1 answer
  • Determine in symbols an expression for the magnetic force exerted on the falling bar (and determine the direction of that force)
    14·1 answer
  • How to do this question
    6·1 answer
  • Melting butter is a physical change. Which best describes what is happening?
    8·1 answer
  • Why are viruses hard to fight
    10·1 answer
  • Explain the working of thermos flask in simple and easy words ​
    8·1 answer
  • Arrange the following types of electromagnetic radiation in order of increasing (lowest to highest) frequency from left to right
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!