λ=v/f
λ-wavelength
v-speed
f-frequency
we have the wavelength(6.2 x 10^-6meters) and we use the speed of light which is equal to 3*10^8m/s
6.2*10^-6m=3*10^8m/s/f
f=(3*10^8m/s)/(6.2*10^-6)≈0.48*10^14Hz
Answer:
38 N, 40.0° below the horizontal
Explanation:
Force exerted by an object equals mass times acceleration of that object: F = m ⨉ a. To use this formula, you need to use SI units: Newtons for force, kilograms for mass, and meters per second squared for acceleration.
Answer:
10.09 N
Explanation:
Analogously to Newton's second law, torque can be defined as:

Here, I is the moment of inertia and
is the angular acceleration. We have:

Torque is the vector product of the position vector of the point at which the force is applied by the force vector:

Since the effective lever arm is perpendicular to the force, the angle between them is
. The magnitud of this vector product is defined as:
.
Solving for F and replacing the known values:

Answer:
λ = a
Explanation:
This is a diffraction exercise that is described by the expression
a sin θ = m λ
sin θ = m λ/ a
the first zero of the diffraction occurs for m = 1
sin θ = λ / a
angles are generally very small and are measured in radians
sin θ = θ = y / x
we substitute
the width of the central maximum is twice the distance to zero
w = 2y
in the exercise indicate that this width is equal to twice the distance to the screen (2x)
W = 2x
2y = 2x
we substitute
1 = λ/ a
λ = a
we see that the width of the slit is equal to the wavelength used.
To solve this problem we will apply the concepts related to energy conservation, so the potential energy in the package must be equivalent to its kinetic energy. From there we will find the speed of the package in the vertical component. The horizontal component is given, as it is the same as the one the plane is traveling to. Vectorially we will end up finding its magnitude. So,


Here,
m = Mass
g = Gravity
h = Height
v = Velocity
Rearranging to find the velocity

Replacing,


Using the vector properties the magnitude of the velocity vector would be given by,



Therefore the package is moving to 66.2m/s