In simpler terms, a proton and neutron weigh 1 amu (atomic mass unit) each.
The nucleus has 15 protons and 18 neutrons. Since a proton's and a neutron's weight is only 1 amu, we can simply add the number of protons and neutrons to find the total mass of the nucleus:
The nucleus' mass is 33 amu.
Solution :
a). From Newtons second law,
F = ma
The total tension force is 2T.
∴ 2T - (m + M)g = (m+ M)a
Then
b). From the person,
F = ma
T - Mg + N = Ma
or N = Ma + Mg - T
= (63 x 9.8) + (52 x 9.8) - 600
= 617.4 + 509.6 - 600
= 527 N
Answer:
v=3.73m/s,
Explanation:
In order to solve this problem, we must first draw a diagram that will represent the situation (See attached picture).
So there are two ways in which we can solve this proble. One by using integrls and the other by using energy analysis. I'll do it by analyzing the energy of the system.
So first, we ned to know what the constant of the spring is, so we can find it by analyzing the energy on points A and C. So we get the following:
where K represents kinetic energy, U represents potential energy and W represents work.
We know that the kinetic energy in C will be zero because its speed is supposed to be zero. We also know the potential energy due to the gravity in C is also zero because we are at a height of 0m. So we can simplify the equation to get:
so now we can use the respective formulas for kinetic energy and potential energy, so we get:
so we can now solve this for k, which is the constant of the spring.
and now we can substitute the respective data:
Which yields:
k= 9300N/m
Once we got the constant of the spring, we can now find the speed of the elevator at point B, which is one meter below the contact point, so we do the same analysis of energies, like this:
In this case ther are no zero values to eliminate so we work with all the types of energies involved in the equation, so we get:
and we can solve for the Velocity in B, so we get:
we can now input all the data directly, so we get:
which yields:
which is the first answer.
Now, for the second answer we need to find the acceleration of the elevator when it reaches point B, for which we need to build a free body diagram (also included in the attached picture) and to a summation of forces:
so we get:
Supposing the acceleration is positive when it points upwards.
So we can solve that for the acceleration, so we get:
or
and now we substitute the data we know:
which yields:
