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Anarel [89]
2 years ago
13

The speed limit on some interstate highways is roughly 90 km/h. (a) What is this in meters per second

Physics
1 answer:
attashe74 [19]2 years ago
7 0

Answer:

25 m/s

Explanation:

⠀⠀⠀⇒ Speed = 90 km/h

⠀⠀⠀⇒ Speed = 90 km/60 min [As 1 hr = 60 min]

⠀⠀⠀⇒ Speed = (90 × 1000) m/(60 × 60)sec

⠀⠀⠀⇒ Speed = 90000 m/3600 sec

⠀⠀⠀⇒ Speed = 900 m/36 sec

⠀⠀⠀⇒ Speed = 300 m/12 sec

⠀⠀⠀⇒ Speed = 100 m/4 sec

⠀⠀⠀⇒ Speed = 25 m/s

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A 1000 kg elevator accelerates upward at 1.0 m/s2 for 10 m, starting from rest. a. How much work does gravity do on the elevator
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Here you go mate. Hope it helps u. Pls follow me in reddit lol username: RobloxNoob2006

5 0
3 years ago
A very long insulating cylinder has radius R and carries positive charge distributed throughout its volume. The charge distribut
blsea [12.9K]

Answer:

1.E(r) = \frac{\alpha}{4\pi \epsilon_0}(2 - \frac{r}{R})

2.E(r) = \frac{1}{4\pi \epsilon_0}\frac{\alpha R}{r}

3.The results from part 1 and 2 agree when r = R.

Explanation:

The volume charge density is given as

\rho (r) = \alpha (1-\frac{r}{R})

We will investigate this question in two parts. First r < R, then r > R. We will show that at r = R, the solutions to both parts are equal to each other.

1. Since the cylinder is very long, Gauss’ Law can be applied.

\int {\vec{E}} \, d\vec{a} = \frac{Q_{enc}}{\epsilon_0}

The enclosed charge can be found by integrating the volume charge density over the inner cylinder enclosed by the imaginary Gaussian surface with radius ‘r’. The integration of E-field in the left-hand side of the Gauss’ Law is not needed, since E is constant at the chosen imaginary Gaussian surface, and the area integral is

\int\, da = 2\pi r h

where ‘h’ is the length of the imaginary Gaussian surface.

Q_{enc} = \int\limits^r_0 {\rho(r)h} \, dr = \alpha h \int\limits^r_0 {(1-r/R)} \, dr = \alpha h (r - \frac{r^2}{2R})\left \{ {{r=r} \atop {r=0}} \right. = \alpha h (\frac{2Rr - r^2}{2R})\\E2\pi rh = \alpha h \frac{2Rr - r^2}{2R\epsilon_0}\\E(r) = \alpha \frac{2R - r}{4\pi \epsilon_0 R}\\E(r) = \frac{\alpha}{4\pi \epsilon_0}(2 - \frac{r}{R})

2. For r> R, the total charge of the enclosed cylinder is equal to the total charge of the cylinder. So,

Q_{enc} = \int\limits^R_0 {\rho(r)h} \, dr = \alpha \int\limits^R_0 {(1-r/R)h} \, dr = \alpha h(r - \frac{r^2}{2R})\left \{ {{r=R} \atop {r=0}} \right. = \alpha h(R - \frac{R^2}{2R}) = \alpha h\frac{R}{2} \\E2\pi rh = \frac{\alpha Rh}{2\epsilon_0}\\E(r) = \frac{1}{4\pi \epsilon_0}\frac{\alpha R}{r}

3. At the boundary where r = R:

E(r=R) = \frac{\alpha}{4\pi \epsilon_0}(2 - \frac{r}{R}) = \frac{\alpha}{4\pi \epsilon_0}\\E(r=R) = \frac{1}{4\pi \epsilon_0}\frac{\alpha R}{r} = \frac{\alpha}{4\pi \epsilon_0}

As can be seen from above, two E-field values are equal as predicted.

4 0
3 years ago
A person that is sleeping on her stomach rolls over so that she is now sleeping on her back. The person moved from the ________
Elza [17]

Answer:

c. prone; supine

Explanation:

3 0
2 years ago
A 5.0 kg wooden block is in free fall at 10 m/s. What is the Kinetic Energy for the wooden block?
andre [41]

Answer:

250 J

Explanation:

Apply the formula:

K = 1/2.m.v²

K = 1/2.5.10²

K = 1/2.5.100

K = 5.50

K = 250 Joules

But, remember that if the speed is accelerating or not, if it is, then we need to know the point in time that the question is asking for the Kinetic Energy.

In this case, I think it is just a constant speed.

4 0
3 years ago
Can we use momentum to see how fast the earth is going?
Kisachek [45]

Yes, if we know the Earth's mass

Explanation:

The momentum of an object is a vector quantity given by the equation

p=mv

where

m is the mass of the object

v is its velocity

In this case, we are asked if we can find the velocity of the Earth by starting from its momentum. Indeed, we can. In fact, we can rewrite the equation above as

v=\frac{p}{m}

Therefore, if we know the momentum of the Earth (p) and we know its mass as well (m), we can solve the formula to find the Earth's velocity.

Learn more about momentum:

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#LearnwithBrainly

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3 years ago
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