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Hitman42 [59]
3 years ago
5

The pressure of a gas in a sealed container is 152 mm hg. This translates to?

Chemistry
1 answer:
Mashcka [7]3 years ago
5 0
<span>the answer is 0.2 ATM</span>
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A chemist wants to make 6.5 L of a 0.340 M CaCl2 solution. Part A What mass of CaCl2 (in g) should the chemist use? Express your
katovenus [111]

Answer:

The answer to your question is 245 grams

Explanation:

Data

Volume 6.5 L

Molarity = 0.34

mass of CaCl₂ = ?

Process

1.- Calculate the molar mass of CaCl₂

molar mass = (1 x 40) + (2 x 35.5)

                   = 40 + 71

                   = 111 g

2.- Convert the grams to moles

                       111 g of CaCl₂ -------------- 1 mol

                         x                   ---------------0.34 mol

                         x = (0.34 x 111) / 1

                         x = 37.74 g

3.- Calculate the total mass

                        37.74 g ------------------ 1 L

                            x        ------------------ 6.5 L

                            x = (6.5 x 37.74) / 1

                            x = 245.31

3 0
3 years ago
I’ll give BRAINLIEST please answer this question fast
geniusboy [140]

Answer:

i think its d im not sure

Explanation:

7 0
3 years ago
The water cycle is the __________________ by which water __________________ through the ____________________ and atmosphere.
zhenek [66]

Answer:

is the process, water circulates , the earth's ocean

Explanation:

7 0
3 years ago
Briefly describe how the pH of a colourless solution could be measured using a universal indicator​
Firdavs [7]

Answer:

Universal indicator can show us how strongly acidic or alkaline a solution is, not just that the solution is acidic or alkaline. This is measured using the pH scale , which runs from pH 0 to pH 14.

Explanation:

~Hope this helps

4 0
3 years ago
a solution is made by dissolving cadmium fluoride (CdF2 Ksp =6.44×10 −3 ) in 100.0 mL of water until excess solid is present. So
Lunna [17]

Answer:

Answers are in the explanation

Explanation:

Ksp of CdF₂ is:

CdF₂(s) ⇄ Cd²⁺(aq) + 2F⁻(aq)

Ksp = 6.44x10⁻³ = [Cd²⁺] [F⁻]²

When an excess of solid is present, the solution is saturated, the molarity of Cd²⁺ is X and F⁻ 2X:

6.44x10⁻³ = [X] [2X]²

6.44x10⁻³ = 4X³

X = 0.1172M

<h3>[F⁻] = 0.2344M</h3><h3 />

Ksp of LiF is:

LiF(s) ⇄ Li⁺(aq) + F⁻(aq)

Ksp = 1.84x10⁻³ = [Li⁺] [F⁻]

When an excess of solid is present, the solution is saturated, the molarity of Li⁺ and F⁻ is XX:

1.84x10⁻³ = [X] [X]

1.84x10⁻³ = X²

X = 0.0429

<h3>[F⁻] = 0.0429M</h3><h3 /><h3>The solution of CdF₂ has the higher fluoride ion concentration</h3>
7 0
3 years ago
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