Answer:
Use the formula
g = GM/R^2
where
g = acceleration of gravity on moon
G = universal gravitational constant
= 6.67 x 10^-11 m^3/kg-s^2
M = mass of the moon
R = radius of the moon
solving for R, we get
R = 1.74 x 10^6 kg
The equation is garbled and the question is missing.
I found this equation for the same statement:
S = - 2.7t ^2 + 30t + 6.5
And one question is: after how many seconds is the ball 12 feet above the moon's surface?
Given that S is the height of the ball, you just have to replace S with 12 and solve for t.
=> 12 = - 2.7 t^2 + 30t + 6.5
=> 2.7t^2 - 30t - 6.5 + 12 = 0
=> 2.7t^2 - 30t + 5.5 = 0
Now you can use the quadratic equation fo find t:
t = { 30 +/- √ [30^2) - 4(2.7)(5.5)] } / (2*2.7)
=> t = 0.186s and t = 10.925 s
Answer: after 0.186 s the ball is at 12 feet over the surface, and again 10.925 s
Answer:
Explanation:
Mass of the Jupiter is 319 times more than that of the earth but its acceleration due to gravity is only 2.5 times more than the earth because the radius of the Jupiter is about 11 times greater than the earth.
