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victus00 [196]
3 years ago
14

the senior class at high school A rented and filled 12 vans and 3 buses with243 students. high school B rented and filled 4 vans

and 4 buses with 204 students. each van and each bus carried the same number of students. Find the number of students in each van in each bus.
Mathematics
1 answer:
bezimeni [28]3 years ago
5 0
12v + 3b = 243
4v + 4b = 204....multiply by -3
-------------------
12v + 3b = 243
-12v - 12b = - 612 (result of multiplying by -3)
-------------------add
-9b = - 369
b = -369/-9
b = 41 <=== each bus holds 41 students

4v + 4b = 204
4v + 4(41) = 204
4v + 164 = 204
4v = 204 - 164
4v = 40
v = 40/4
v = 10 <== each van holds 10 students

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The life of Sunshine CD players is normally distributed with a mean of 4.1 years and a standard deviation of 1.3 years. A CD pla
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Using the normal distribution, we have that:

a) The sketch of the situation is given at the end of this answer.

b) The probability is:

P(2.8 \leq X \leq 7) = 0.8284

In a normal distribution with mean and standard deviation , the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
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In this problem:

  • Mean of 4.1 years, thus \mu = 4.1.
  • Standard deviation of 1.3 years, thus \sigma = 1.3.

Item a:

The part between 2.8 and 7 years is shaded on the sketch given at the end of this answer.

Item b:

The probability is the <u>p-value of Z when X = 7 subtracted by the p-value of Z when X = 2.8</u>, thus:

X = 7:

Z = \frac{X - \mu}{\sigma}

Z = \frac{7 - 4.1}{1.3}

Z = 2.23

Z = 2.23 has a p-value of 0.9871.

X = 2.8:

Z = \frac{X - \mu}{\sigma}

Z = \frac{2.8 - 4.1}{1.3}

Z = -1

Z = -1 has a p-value of 0.1587.

0.9871 - 0.1587 = 0.8284, thus:

P(2.8 \leq X \leq 7) = 0.8284

A similar problem is given at brainly.com/question/25151638

7 0
3 years ago
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