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IRINA_888 [86]
3 years ago
9

Which element increases its oxidation number in this reaction? 2Na + 2H2O → 2NaOH + H2

Chemistry
1 answer:
sammy [17]3 years ago
6 0

Answer:

Sodium

Explanation:

-Gradpoint

You might be interested in
Which substance is a base? HCOOH RbOH H2CO3 NaNO3
Alex Ar [27]

Answer:

RbOH

Explanation:

For this question, we have to remember what is the definition of a base. A base is a compound that has the <u>ability to produce hydroxyl ions</u> OH^-, so:

AOH~->~A^+~+~OH^-

With this in mind we can write the <u>reaction for each substance:</u>

HCOOH~->~HCOO^-~+~H^+

RbOH~->~Rb^+~+~OH^-

H_2CO_3~->~CO_3^-^2~+~2H^+

NaNO_3~->~Na^+~+~NO_3^-

The only compound that fits with the definition is RbOH, so this is our <u>base</u>.

I hope it helps!

6 0
3 years ago
Read 2 more answers
Give an example based upon particle argument​
lesya692 [45]

Answer:

squeezing syringes contain gas

7 0
2 years ago
How many rods will equal 247 inches
d1i1m1o1n [39]
It will be 1.247 rods that will equal 247 inches.
3 0
3 years ago
Read 2 more answers
How many moles are represented by 3.01x10^23 helium atoms
Alex787 [66]

Answer:

b. 0.50 moles

Explanation:

To solve this problem we use <em>Avogadro's number</em> (6.023x10²³ atoms/mol).

By <u>dividing the number of atoms (or molecules) by that number</u>, we can calculate how many moles they represent.

  • 3.01x10²³ atoms ÷ 6.023x10²³ atoms/mol = 0.50 moles

So the answer is option b. 0.50 moles.

4 0
2 years ago
If you determine the molar heat of neutralization for an acid is 49.1 kJ/mol and the accepted value is found to be 55.2 kJ/mol,
zhenek [66]

Answer: % Errror = 11.05%

Explanation:

Percentage error is the difference between the measured value and the theoretical value as expressed in percent.

That is;

% Error =

( Theoretical value -measured value) /(Theoretical value) × 100

Theoretical value =55.2kJ

Measured value = 49.1kJ

% Error = (55.2-49.1)/(55.2) ×100

%Error = 6.1/55.2 ×100

% Error = 0.1105 ×100

% Error = 11.05

Therefore the percentage error is 11.05%

5 0
3 years ago
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