oops pls forgive me I accidentally did the wrong question.
Answer:
CaCl2
Explanation:
For every calcium there's 2 chlorine
DR is the correct answer
hope this helps
Answer:
25.7 kJ/mol
Explanation:
There are two heats involved.
heat of solution of NH₄NO₃ + heat from water = 0
q₁ + q₂ = 0
n = moles of NH₄NO₃ = 8.00 g NH₄NO₃ × 1 mol NH₄NO₃/80.0 g NH₄NO₃
∴ n = 0.100 mol NH₄NO₃
q₁ = n * ΔHsoln = 0.100 mol * ΔHsoln
m = mass of solution = 1000.0 g + 8.00 g = 1008.0 g
q₂ = mcΔT = 58.0 g × 4.184 J°C⁻¹ g⁻¹ × ((20.39-21)°C) = -2570.19 J
q₁ + q₂ = 0.100 mol ×ΔHsoln – 2570.19 J = 0
ΔHsoln = +2570.19 J /0.100 mol = +25702 J/mol = +25.7 kJ/mol
Answer:
n = 2 mol
Explanation:
Given data:
Pressure = standard = 1 atm
Temperature = standard = 273.15 K
Volume = 44.8 L
Number of moles = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
1 atm × 44.8 L = n × 0.0821 atm.L/ mol.K × 273.15 K
44.8 atm.L = n × 22.43 atm.L/ mol
n = 44.8 atm.L / 22.43 atm.L/ mol
n = 2 mol
