the answer is definitely A.
C is probably the correct one
Answer:
we got time and velocity over time.
so the distance is again the area underneath the graph
for a triangle with known base and height it's
4*10 / 2
distance traveled is 20
deceleration occurs when velocity decreases. that happens from t=2 till t=4
in 2 time-units we loose 10 units of velocity, so we decelerate by 5 units per 1 time
a (from t=2 to t=4) = -5v/t
Explanation:
It is given that, the height of a certain tower is 862 feet i.e to reach on the ground the object should travel, s = 862 feet
The distance traveled by a freely falling object is given by :
![s(t)=16t^2](https://tex.z-dn.net/?f=s%28t%29%3D16t%5E2)
![16t^2=862](https://tex.z-dn.net/?f=16t%5E2%3D862)
![t=\sqrt{53.875}](https://tex.z-dn.net/?f=t%3D%5Csqrt%7B53.875%7D)
t = 7.34 seconds
So, the object will take 7.34 seconds to fall to the ground from the top of the building. Hence, this is the required solution.