.A particle starts on the origin. It is pushed back to -5.7 m in 2.1 s. Then it is pushed
2 answers:
Answer:
The average velocity of the particle is 1.76 m/s.
Explanation:
Given that,
Distance = -5.7 m
Time t = 2.1 s
Forward distance = 7.3 m
Total time = 9.5 sec
We need to calculate the average velocity of the particle
Average velocity :
Average velocity is equal to the displacement divided by change in time.
Where, D = displacement
t = change in time
Hence, The average velocity of the particle is 1.76 m/s.
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