Question

.A particle starts on the origin. It is pushed back to -5.7 m in 2.1 s. Then it is pushed

Answer 1

Answer: The average velocity is -0.965m/s

Explanation: The first step is to calculate the two velocities is both directions. A velocity is a distance per unit time.

V=d/ t

=-5.7/2.1

=-2.7m/s

For the other direction the velocity is

V=7.3/9.5

=0.77m/s

The average velocity the add the velocities and divide them by 2.

V=-2.7+0.77/2

V= 0.965m/s

Answer 2

Answer:

The average velocity of the particle is 1.76 m/s.

Explanation:

Given that,

Distance = -5.7 m

Time t = 2.1 s

Forward distance = 7.3 m

Total time = 9.5 sec

We need to calculate the average velocity of the particle

Average velocity :

Average velocity is equal to the displacement divided by change in time.

$v = \dfrac{\Delta D}{\Delta t}$

Where, D = displacement

t = change in time

$v=\dfrac{7.3-(-5.7)}{9.5-2.1}$

$v=1.76\ m/s$

Hence, The average velocity of the particle is 1.76 m/s.