Answer:
1.73 m/s²
Explanation:
Given:
Δx = 250 m
v₀ = 0 m/s
t = 17 s
Find: a
Δx = v₀ t + ½ at²
250 m = (0 m/s) (17 s) + ½ a (17 s)²
a = 1.73 m/s²
Answer:
the electric field strength on the second one is 2.67 N/C.
Explanation:
the electric fiel on the first one is:
E1 = k×q/(r^2)
r^2 = k×q/(E1)
= (9×10^9)×(q)/(24.0)
= 375000000q
then the electric field on the second one is:
E2 = k×q/(R^2)
we know that R = 3r
R^2 = 9×r^2
E2 = k×q/(9×r^2)
= k×q/(9×375000000q)
= k/(9×375000000)
= (9×10^9)/(9×375000000)
= 2.67 N/C
Therefore, the electric field strength on the second one is 2.67 N/C.
Answer:
353225
Explanation:8uhhhhhhhhhlkgg
Answer:
The answer to your question is the letter A) F = 9.23 x 10⁻⁷ N
Explanation:
Data
q₁ = -6.25 x 10⁻⁹ C
q₂ = -6.25 x 10⁻⁹ C
d = 0.617 m
k = 9 x 10⁹ Nm²/C²
F = ?
Formula
F = k q₁q₂ /r²
-Substitution
F = (9 x 10⁹)(-6.25 x 10⁻⁹)(-6.25 x 10⁻⁹) / (0.617)²
-Simplification
F = 3.512 x 10⁻⁷ / 0.381
-Result
F = 9.227 x 10⁻⁷ N ≈ 9.23 x 10⁻⁷ N
Hello!
First one we can use that PE=mgh so we have
4.37*10^5J/(9.12*10^3kg*9.80m/s^2)= 4.89m
Second one we can use Newton’s Second Law
F=ma and in this case F=mg so we have
g= 3.28*10^-2N/6*10^-3kg = 5.47m/s^2
Hope this helps. Any questions please ask. Thank you.
