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3 years ago

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What would be the orbital speed and period of a satellite in orbit 0.82 ✕ 108 m above the earth?

1 answer:

Ivenika [448]3 years ago

3 0

The answer should be 88.56

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iVinArrow [24]

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3 years ago

A 3500 kg spaceship is in a circular orbit 220 km above the surface of Earth. It needs to be moved into a higher orbit of 360 km

Vitek1552 [10]

Answer:

The work done is calculated as $0.044\times 10^{11}\ J$

Solution:

As per the question:

Mass of the spaceship, m = 3500 kg

Height of the orbit, h = 220 km

Mass of the earth, $M_{e} = 5.97\times 10^{24}\ kg$

Height of the higher orbit, h' = 360 km

Radius of the orbit, $R = 6.37\times 10^{6}\ km$

Now,

The work done is given by the change in the gravitational potential energy:

Gravitational Potential Energy, U = $- \frac{GM_{e}m}{R + h}$

Now, for the lower orbit:

$U_{l} = - \frac{GM_{e}m}{R + h}$

$U_{l} = - \frac{6.67\times 10^{- 11}\times 5.97\times 10^{24}\times 3500}{6.37\times 10^{6} + 220\times 10^{3}}$

$U_{l} = - 2.115\times 10^{11}\ J$

For upper orbit:

$U_{U} = - \frac{GM_{e}m}{R + h}$

$U_{u} = - \frac{6.67\times 10^{- 11}\times 5.97\times 10^{24}\times 3500}{6.37\times 10^{6} + 360\times 10^{3}}$

$U_{U} = - 2.071\times 10^{11}\ J$

Change in the gravitational Potential energy:

$\Delta U = U_{U} - U_{l} = - 2.071\times 10^{11} - (- 2.115\times 10^{11}) = 0.044\times 10^{11}\ J$

Therefore, the work done:

$W = 0.044\times 10^{11}\ J$

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3 years ago

A square coil (length of side = 24 cm) of wire consisting of two turns is placed in a uniform magnetic field that makes an angle

dalvyx [7]

Explanation:

It is given that,

Length of side of a square, l = 24 cm = 0.24 m

The uniform magnetic field makes an angle of 60° with the plane of the coil.

The magnetic field increases by 6.0 mT every 10 ms. We need to find the magnitude of the emf induced in the coil. The induced emf is given by :

$\epsilon=N\dfrac{d\phi}{dt}$

$\dfrac{d\phi}{dt}$ is the rate of change if magnetic flux.

$\phi=BA\ cos\theta$

$\theta$ is the angle between the magnetic field and the normal to area vector.

$\theta=90-60=30$

$\epsilon=NA\dfrac{dB}{dt}\times cos30$

$\epsilon=2\times (0.24\ m)^2\times \dfrac{6\ mT}{10\ mT}\times cos(30)$

$\epsilon=0.0598\ T$

$\epsilon=59.8\ mT$

or

EMF = 60 mT

So, the magnitude of emf induced in the coil is 60 mT. Hence, this is the required solution.

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Which of the following will change if you apply unbalanced forces to an object?

bearhunter [10]

The velocity of the object will change, thus changing its position.

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A 2.00 m long string is vibrated 5.00 times every second to create a standing wave with 2 antinodes.

Diano4ka-milaya [45]

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3 years ago