3 years ago

What would be the orbital speed and period of a satellite in orbit 0.82 ✕ 108 m above the earth?

Physics

1 answer:

Ivenika [448]3 years ago

3 0

The answer should be 88.56

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For an object with a given mass on Earth, calculate the weight of the object with the mass equal in magnitude to the number repr

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Answer: The weight of the object is 29.4 N

Explanation:

To calculate the weight of the object, we use the equation:

$W=m\times g$

where,

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An object is dropped from a bridge. A second object is thrown downwards 1.00 s later. They both reach the water 20.0 m below at

Deffense [45]

Answer:

$v_{o}=-14.60m/s$

Explanation:

Kinematics equation for first Object:

$y(t)=y_{o}+v_{o}t-1/2*g*t^{2}$

but:

$v_{o}=0m/s$ The initial velocity is zero

$y_{o}=20m$

it reach the water at in instant, t1, y(t)=0:

$0=y_{o}-1/2*g*t_{1}^{2}$

$t_{1}=\sqrt{2y_{o}/g}=\sqrt{2*20/9.81}=2.02s$

Kinematics equation for the second Object:

The initial velocity is zero

$y(t)=y_{o}+v_{o}t-1/2*g*t^{2}$

but:

$y_{o}=20m$

it reach the water at in instant, t2, y(t)=0. If the second object is thrown 1s later, t2=t1-1=1.02s

$0=y_{o}+v_{o}t_{2}-1/2*g*t_{2}^{2}$

$v_{o}=1/(t_{2})*(1/2*g*t_{2}^{2}-y_{o})=(1/1.02)*(1/2*9.81*1.02^{2}-20)=-14.60m/s$

The velocity is negative, because the object is thrown downwards.

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3 years ago