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Nadya [2.5K]
3 years ago
8

Solve for x. y=7x−7z−9

Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
6 0
You have to isolate the variable so you need to add 7z and 9 to both sides. You then get y+ 7z+ 9= 7x. Then divide 7x from both sides. The equation becomes x= y/7+ z + 9/7.
I hope this helps love! :)
AleksandrR [38]3 years ago
5 0

Answer:

The value of x is x=\frac{y+7z+9}{7}

Step-by-step explanation:

Consider the provided equation.  

y=7x-7z-9

We need to solve the equation for x.

Add 7z to both the sides.

y+7z=7x-7z+7z-9

y+7z=7x-9

Add 9 to both the sides.

y+7z+9=7x-9+9

y+7z+9=7x

Divide both sides by 7.

x=\frac{y+7z+9}{7}

Hence the value of x is x=\frac{y+7z+9}{7}.

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One batch of mooncakes contains 1/4 tablespoons of kansui. How many tablespoons of kansui are
Ghella [55]

From the division property, the required kansui is 5/32 tablespoon.

What is division?

One of the four fundamental arithmetic operations, or the process by which two or more numbers are added together to create a new number, is division. Multiplication, addition, and subtraction round out the list of operations.

Given that a batch of mooncake contains 1/4 tablespoon of kansui.

Given batch of mooncake is 1 3/5 = 8/5

Therefore,

\frac{\frac{1}{4}}{\frac{8}{5}}\\=\frac{1}{4} \times \frac{5}{8}\\=\frac{5}{32}

Hence, the required kansui is 5/32 tablespoon.

To learn more about division from the given link

brainly.com/question/25289437

#SPJ9

3 0
1 year ago
What is the scale factor for the set of similar figures? <br> Is it 0.62
NNADVOKAT [17]
k=\dfrac{9.6}{6}=1.6
5 0
3 years ago
If p is a true statement and q is false, what is the truth value of p ∨ q? T F → T T F → F F T → T F T → F
stiks02 [169]

Answer:

If p is a true statement and q is false, what is the truth value of p ∨ q?

<u>T F → T</u> T F → F F T → T F T → F

Step-by-step explanation:

because it says P is true and q is false

4 0
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Read 2 more answers
Listed below are the weights in pounds of 11 players randomly selected from the roster of the Seattle Sea-hawks when they won Su
weeeeeb [17]

Answer:

No. These measures show a thinner team of NFL players according to the mean, variance, standard deviation, and quartiles.

Step-by-step explanation:

1) The measures of variation, namely The Range, Variance, Quartiles, Interquartiles, Sum of Squares, etc. shows us how the data are dispersed.

The Range Δ is calculated:

\Delta =305-189=116 Maximum value - Minimum value for weight

Mean:

\bar{x}=\frac{189+254+235+225+190+305+202+190+252+305}{11}\approx 231.09 \:pounds

Variance:

s^{2}=\frac{\sum_{i=1}^{n} (x_i-\bar{x})^{2}}{n-1}\Rightarrow s=1923.69\\

The Standard Deviation of the sample

s=\sqrt{s^{^{2}}}\Rightarrow s\approx 43.86\\

2) Since there is no preceding exercise, the comparison was made to a recent study in which a NFL player average weight is about 245 pounds (average),

Since 25% of this list are player whose weight is 192.5 lbs and 50% (2nd Quartile) =225 lbs , finally only at the 3rd Quartile we have players above the regular NFL average with 253. This, added with the other data, allow us to say that this list is not a typical of all NFL players.

4 0
3 years ago
Worth 10 points if correct answer you will get brainliest :)
barxatty [35]

Answer:

16/21

Step-by-step explanation:

5 0
3 years ago
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