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DaniilM [7]
3 years ago
10

16. The energy absorbed in 10minutes by an electrical heater is 1.5 MJ. The supply voltage is 240 V. calculate: a) The current d

rawn b) The quantity of electricity in Coulombs taken in 5 minutes c) The energy absorbed in 100 hours.
Physics
1 answer:
dsp733 years ago
5 0

Answer:

If by 1.5 MJ you mean 1.5E6 Joules then

W = P t    = power X time

W / t = P   power

P = 1.5E6 J / 600 sec = 2500 J / s

P = I V

a) I = 2500 J/s / (240 J/c) = 10.4 C / sec  = 10.4 amps

b) Q = I t = 10.4 C / sec * 300 sec = 3120 Coulombs

c)  E = P * t = 2500 J / sec * 100 hr * 3600 sec / hr = 9.0E8 Joules

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How far would a horse that rides at 8.1 m/s travel and 8.5 minutes
Xelga [282]
V = S/t

The time is in minutes, it needs to be converted to seconds, because the Velocity 8.1meters/second.

1 min -------- 60 secs
8.5 min -------- x secs
-> x = 8.5 . 60
-> x = 510secs

-> 8.1 = S/510
-> 510 x 8.1 = S
-> S = 4131 meters
3 0
4 years ago
If an object of mass m1 = 0.55 ???????? is sliding without friction in the +x-direction on a level surface at a speed of ????1 =
tatiyna

Answer:

ME = 0.14 J

P = 0.396 kg m/s

Explanation:

As we know that for perfectly elastic collision total mechanical energy is always conserved

so we will have

ME = \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2

ME = \frac{1}{2}0.55(0.72^2) + \frac{1}{2}0.55(0^2)

ME = 0.14 J

now we also know that total moment of the system is conserved in any collision because there is no external force on it

so we will have

P = m_1v_1 + m_2v_2

P = 0.55(0.72) + 0

P = 0.396 kg m/s

6 0
4 years ago
An object accelerates 3.0 m/s2 when a force of 6.0 N is applied to it. What is the mass of the object?
makvit [3.9K]

Answer:

<h2>2 kg</h2>

Explanation:

The mass of the object can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{6}{3}  \\

We have the final answer as

<h3>2 kg</h3>

Hope this helps you

5 0
3 years ago
What is the electrical force between q2 and q3? Recall that k = 8. 99 × 109 N•meters squared over Coulombs squared. 1. 0 × 1011
nlexa [21]

Force on the particle is defined as the application of the force field of one particle on another particle. the electrical force between q₁ and q₃ will be –1. 1 × 10¹¹ N.

<h3>What is electric force?</h3>

Force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force.

The electric force in the second case will be the same as in the first case. Therefore the force on the particle will be the same.

\rm F= K\frac{q_2q_3}{r^2}

\rm F= 9\times 10^9 \times \frac{1.6 \times 10^{-13}\times 1.6\times10^{-13}}{(0.5)^2}

\rm F=  - 1. 1 \times 10^{11 }N

Hence the electrical force between q₁ and q₃ will be –1. 1 × 10¹¹ N.

To learn more about the electric force refer to the link;

brainly.com/question/1076352

4 0
3 years ago
Help in physics please :(((​
Arlecino [84]

Answer:

I am sorry I can't draw graphical ok how to draw the graph where what is your position the displacement of time and work 7 kilometres east in 2 hours and what will happen to the time and 72 in 1 hour what is the displacement you after take the displacement formula that is total time taken divided by the distance travelled ok displacement and distance travelled is different about its terms ok

8 0
3 years ago
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