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3 years ago

How do you know when to use each equations of motion while solving numericals? Please help as soon as possible .

Physics

1 answer:

posledela3 years ago

8 0

Answer:

You must catch the known-variables and the unknown-variables from the question to use the right equation.

Explanation:

Whenever you are solving a numerical, follow these steps:

1. From the asked question, jot down the given variables like initial velocity, total time, or acceleration etc.

2. After that, write the variable which is asked and put a question mark next to it.

3. Now that you have the given information and asked information in terms of variables, you should see which equation has all those variables. It might be helpful to jot down all three equations of motion on a side of paper. Once you have all three equations in front of you, you can easily spot the equation which has all the known and unknown variables in it.

Note: Sometimes, you might have to use more than one equations to get to the asked variable. You can think of that as two question instead of one, where you have to find out two variable instead of one.

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First we will find the mass of the stone

As it is given that stone is spherical in shape so first we will find its volume

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$V = \frac{4}{3}\pi *(\frac{0.06}{2})^3$

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Now it is given that it's specific gravity is 10.8

So density of rock is

$\rho = 10.8 * 10^3 kg/m^3$

mass of the stone will be

$m = \rho V$

$m = 10.8* 10^3 * 1.13 * 10^{-4}$

$m = 1.22 kg$

now change in potential energy is given as

$\Delta U = mgH$

here

g = gravity on planet = 0.278 m/s^2

H = height lifted upwards = 15 cm

$\Delta U = 1.22* 0.278 * 0.15$

$\Delta U = 0.051 J$

Now energy supplied by internal circuit of robot is given by

$E = Vit$

V = voltage supplied = 10 V

i = current = 1.83 mA

t = time = 12 s

$E = 10* 1.83 * 10^{-3} * 12$

$E = 0.22 J$

Now efficiency is defined as the ratio of output work with given amount of energy used

$\eta = \frac{\Delta U}{E}*100$

$\eta = \frac{0.051}{0.22} = 0.23$

so efficiency will be 23 %

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3 years ago

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Answer:

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Explanation:

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3 years ago

Read 2 more answers

A 1.20 kg water balloon will break if it experiences more than 530 N of force. Your 'friend' whips the water balloon toward you

soldi70 [24.7K]

Answer:

t = 0.029s

Explanation:

In order to calculate the interaction time at the moment of catching the ball, you take into account that the force exerted on an object is also given by the change, on time, of its linear momentum:

$F=\frac{\Delta p}{\Delta t}=m\frac{\Delta v}{\Delta t}$ (1)

m: mass of the water balloon = 1.20kg

Δv: change in the speed of the balloon = v2 - v1

v2: final speed = 0m/s (the balloon stops in my hands)

v1: initial speed = 13.0m/s

Δt: interaction time = ?

The water balloon brakes if the force is more than 530N. You solve the equation (1) for Δt and replace the values of the other parameters:

$|F|=|530N|= |m\frac{v_2-v_1}{\Delta t}|\\\\|530N|=| (1.20kg)\frac{0m/s-13.0m/s}{\Delta t}|\\\\\Delta t=0.029s$

The interaction time to avoid that the water balloon breaks is 0.029s

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3 years ago