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Doss [256]
3 years ago
14

A container is filled to a depth of 22.0 cm with water. On top of the water floats a 28.0-cm-thick layer of oil with specific gr

avity 0.500. What is the absolute pressure at the bottom of the container? 1 Pa
Physics
1 answer:
Ilya [14]3 years ago
5 0

Answer:104.853 kPa

Explanation:

Given

Depth of water h_2=22 cm

on the top of water a layer of h_1=28 cm oil layer is present

specific gravity of oil \rho _o=0.5\rho _w

Assuming Atmospheric Pressure to be 101.325 KPa

We know Pressure due to Pressure Difference is given by

\Delta P=\rho \times g\times h

\Delta P=\rho _0\times g\times h_1+\rho _w\times g\times h_2

\Delta P=0.5\rho _w\times g\times h_1+\rho _w\times g\times h_2

\Delta P=0.5\times 1000 \times 9.8\times 0.28+1000\times 9.8\times 0.22

\Delta P=1.372\times 10^3+2.156\times 10^3

\Delta P=3.528 kPa

Absolute\ Pressure=Atmospheric\ Pressure+\Delta P=101.325+3.528

Absolute\ Pressure =101.325+3.528=104.853 kPa

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KiRa [710]

Answer: 4 ft/s

Explanation:

Given

height of man=4 ft

speed of person v=8 ft/s

height if street light=12 ft

Let x be the distance between person and street light and y be the length of his shadow

From diagram

as the two triangle ADE and ABC are similar therefore we can say that

\frac{4}{12}=\frac{y}{x+y}

\frac{1}{3}=\frac{y}{x+y}

x+y=3y

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differentiate above Equation w.r.t time we get

\frac{\mathrm{d} x}{\mathrm{d} t}=2\frac{\mathrm{d} y}{\mathrm{d} t}

\frac{\mathrm{d} y}{\mathrm{d} t}=\frac{8}{2}=4 ft/s

6 0
3 years ago
1. A plane travels a distance of 500
Yanka [14]

Answer:

Option C, 139 m/s

Explanation:

s = d/t

s = 500*10^3/3600

s = 138.8 = 139 m/s

5 0
3 years ago
What is the necessary conditions for the production of sound?
TEA [102]

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Answer: Something that's vibrating, and you also need medium for those vibrations to start in.

I hope this helped!

<!> Brainliest is appreciated! <!>

- Zack Slocum

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

8 0
2 years ago
an electron, a proton and a deuteron move in a magnetic field with same momentum perpendicularly. the ratio of the radii of thei
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If an electron, a proton, and a deuteron move in a magnetic field with the same momentum perpendicularly, the ratio of the radii of their circular paths will be:

  • 1: √2 : 1

<h3>How is the ratio of the perpendicular parts obtained?</h3>

To obtain the ratio of the perpendicular parts, one begins bdy noting that the mass of the proton = 1m, the mass of deuteron = 2m, and the mass of the alpha particle  = 4m.

The ratio of the radii of the parts can be obtained by finding the root of the masses and dividing this by the charge. When the coefficients are substituted into the formula, we will have:

r = √m/e : √2m/e : √4m/2e

When resolved, the resulting ratios will be:

1: √2 : 1

Learn more about the radii of their circular paths here:

brainly.com/question/16816166

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6 0
2 years ago
CAN YOU PLS CHECK IF ITS CORRECT I'LL MARK YOU BRAINLIST
Alexus [3.1K]

i think it looks good

yea it correct

BTW yw if it's right

5 0
3 years ago
Read 2 more answers
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