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3 years ago

Does the tension of a string affect the speed of a wave

1 answer:

5 0

Yes , increased tension suggests increased molecular attraction between the molecules of the ropes which affect the increase in the speed of wave.

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A polar bear runs at a speed of 11 m/s and has a mass of 380.2 kg. How much Kinetic energy does the bear have?

Yanka [14]

Answer:

$\boxed{\sf Kinetic \ energy \ of \ the \ bear (KE) = 23002.1 \ J}$

Given:

Mass of the polar bear (m) = 6.8 kg

Speed of the polar bear (v) = 5.0 m/s

To Find:

Kinetic energy of the polar bear (KE)

Explanation:

Formula:

$\boxed{ \bold{\sf KE = \frac{1}{2} m {v}^{2} }}$

Substituting values of m & v in the equation:

$\sf \implies KE = \frac{1}{2} \times 380.2 \times {11}^{2}$

$\sf \implies KE = \frac{1}{ \cancel{2}} \times \cancel{2} \times 190.1 \times 121$

$\sf \implies KE = 190.1 \times 121$

$\sf \implies KE = 23002.1 \: J$

$\therefore$

Kinetic energy of the polar bear (KE) = 23002.1 J

5 0

3 years ago

to what circuit element is an ideal inductor equivalent for circuits with constant currents and voltages?

Marat540 [252]

Answer:

Short circuit

Explanation:

In an ideal inductor circuit with constant current and voltage, it implies that the voltage drop in the circuit is zero (0).

Also, In circuit analysis, a short circuit is defined as a connection between two nodes that forces them to be at the same voltage.

In an ideal short circuit, this means there is no resistance and thus no voltage drop across the connection. That is voltage drop is zero (0).

Therefore, the circuit element is short circuit.

8 0

3 years ago

Which dog has the most kinetic energy? A. A dog of mass 10 kg running with speed 6 m/s B. A dog of mass 8 kg running with speed

Mars2501 [29]

Answer:

J stands for Joules.

A has the most KE

Explanation:

Dog A

En = 1/2 m * v^2
m = 10 kg
v = 6 m/s
En = 1/2 10 * 6^2
En = 5 * 36
En = 180 J

Dog B

En = 1/2 m * v^2
m = 8 kg
v = 4 m/s
En = 1/2 8 * 4^2
En = 4 * 16
En = 64 J

Dog C

En = 1/2 m * v^2
m = 12 kg
v = 5 m/s
En = 1/2 12 * 5^2
En = 6 * 25
En = 150 J

Dog D

En = 1/2 m * v^2
m = 15 kg
v = 3 m/s
En = 1/2 3 * 3^2
En = 1.5 * 9
En = 13.5 J

3 0

3 years ago

Energy derived from hot rocks and fluids beneath the earth’s surface is _____.

yan [13]

Geothermal?
..................

7 0

3 years ago

Read 2 more answers

Charge 9 × 10−18 C is on the y axis a distance 5 m from the origin and charge 9 × 10−18 C is on the x axis a distance d from the

Sergeeva-Olga [200]

Answer:

d = 3.53 m

Explanation:

The Coulomb Force is given as

$\vec{F} = \frac{1}{4\pi\epsilon_0}\frac{q_1q_2}{r^2}\^r$

The x-component of the force is equal to

$F_x = F\cos(\theta) = F\frac{x}{\sqrt{x^2 + y^2}} = \frac{1}{4\pi\epsilon_0}\frac{q_1q_2}{(5^2 + d^2)}\frac{d}{\sqrt{5^2 + d^2}} = \frac{1}{4\pi\epsilon_0}\frac{dq_1q_2}{(5^2 + d^2)^{3/2}}$

This is basically a function of (d). So, the maximum value of this function is the point where its derivative with respect to d is equal to zero.

$\frac{dF_x}{dd} = \frac{kq_1q_2}{(d^2 + 5^2)^{3/2}} - \frac{3d^2kq_1q_2}{(d^2 + 5^2)^{5/2}} = 0\\3d^2 = d^2 + 5^2\\2d^2 = 25\\d = 3.53~m$

8 0

3 years ago