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Lena [83]
3 years ago
8

Please help me with the equations for this! Three uniform spheres are fixed at the positions shown in the diagram. ( there is a

1kg mass .5 m to the right of the origin, a 1kg mass .5m directly above the origen, and a 2kg mass at (.5,.5))Assume they are completely isolated and there are no other masses nearby. If the 0.20 kg particle is placed at (x,y) = (-500 m, 400 m) and released from rest, what will its speed be when it reaches the origin? (c) How much energy is required to separate the three masses so that they are very far apart?
Physics
1 answer:
lora16 [44]3 years ago
7 0
The change in gravitational potential energy due to change in position must be the change in it's kinetic energy as the system is isolated! so find out the potential energies of the two different points!

<span>PE=−[G<span>M1</span><span>M2</span>]÷R

</span><span> Potential energy of a particle due to mass A is not affected by presence of any other mass B !</span>
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The block in the drawing has dimensions L0×2L0×3L0,where L0 =0.5 m. The block has a thermal conductivity of 200 J/(s·m·C˚). In d
Dennis_Churaev [7]

Answer:

Q_p=18000\ J

Q_o=8000\ J

Q_g=72000\ J

Explanation:

Given:

  • Length of block, l=3L_o=3\times 0.5=1.5\ m
  • Breadth of block, b=L_o=0.5\ m
  • height of block, h=2L_o=2\times 0.5=1\ m
  • Thermal conductivity of the block, k=200\ W.m.^{\circ}C
  • Temperature on the hotter side, T_H=37^{\circ}C
  • temperature on the cooler side, T_L=7^{\circ}C
  • time for which the heat flows, t=4\ s

<u>REFER THE ATTACHED IMAGE FOR THE REFERENCE</u>

<em>The rate of heat flow using </em><em>Fourier's law</em><em> of conduction is given as:</em>

\frac{Q}{t}=k.A.\frac{dT}{dx}

<u>Now the amount heat flow perpendicular to the pink surface:</u>

\frac{Q_p}{4}=200\times (0.5\times 1.5).\frac{30}{1}

Q_p=18000\ J

<u>Now the amount heat flow perpendicular to the orange surface:</u>

\frac{Q_o}{4}=200\times (0.5\times 1).\frac{30}{1.5}

Q_o=8000\ J

<u>Now the amount heat flow perpendicular to the green surface:</u>

\frac{Q_g}{4}=200\times (1.5\times 1).\frac{30}{0.5}

Q_g=72000\ J

6 0
4 years ago
Meteor Infrasound A meteor that explodes in the atmosphere creates infrasound waves that can travel multiple times around the gl
kherson [118]

Answer:

0.04455 Hz

Explanation:

Parameters given:

Wavelength, λ = 6.5km = 6500m

Distance travelled by the wave, x = 8830km = 8830000m

Time taken, t = 8.47hours = 8.47 * 3600 = 30492 secs

First, we find the speed of the wave:

Speed, v = distance/time = x/t

v = 8830000/30492 = 289.58 m/s

Frequency, f, is given as velocity divided by wavelength:

f = v/λ

f = 289.58/6500

f = 0.04455 Hz

8 0
3 years ago
The law of conservation of matter states that during a chemical reaction, the amount of matter ​
mixas84 [53]

Answer:

The law of conservation of matter says that in chemical reactions, the total mass of the products must equal the total mass of the reactants.

7 0
3 years ago
How far apart are two conducting plates that have an electric field strength of 8.53 x 103 V/m between them, if their potential
sleet_krkn [62]

Answer:

d=2.7m

Explanation:

From the question we are told that:

Electric Field strength E=8.53 * 10^3 V/m

Potential difference is V= 23.0 kV

Generally the equation for distance is mathematically given by

d=\frac{V}{E}

d=\frac{23.0*10^3}{8.53 * 10^3 V/m}

d=2.7m

5 0
3 years ago
A car is on cruise control at v=30m/s. If the wind resistance is equal to. F=0.42v² what energy will the car expend to drive 1km
weeeeeb [17]

Answer:

D)378kJ

Explanation:

Applying,

E = F×d................ Equation 1

Where E = Energy expanded by the car, F = Wind resistance, d = distance

From the question,

F = 0.42v²............ Equation 2

Susbtitute equation 2 into equation 1

E = 0.42v²d.............. Equation 3

Given: v = 30 m/s, d = 1 km = 1000 m

Substitute these values into equation 3

E = 0.42(30²)(1000)

E = 378000

E = 378 kJ

Hence the right option is D)378kJ

6 0
3 years ago
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