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SSSSS [86.1K]
4 years ago
15

A volleyball player hit he ball with a mass of .25 kg. the average acceleration of the ball is 15.5 m/s^2. how much force did th

e volleyball player apply to the ball?
Physics
2 answers:
sukhopar [10]4 years ago
6 0
F=MA - equation
F=(0.25 kg)(15.5 m/s^2) - multiply the mass and the acceleration
F= 3.875 N - N means Newton (SI unit for force)
Hope this helps 
daser333 [38]4 years ago
5 0
Hey there! I know that the correct answer is 3.87N since I just took the quiz and got that correct! Have a nice day xoxo
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When jumping straight down, you can be seriously injured if you land stiff-legged. One way to avoid injury is to bend your knees
choli [55]

Answer:

a)  F = 1.26 10⁵ N, b)  F = 2.44 10³ N, c)   F_net = 1.82 10³ N  directed vertically upwards

Explanation:

For this exercise we must use the relationship between momentum and momentum

         I = Δp

         F t = p_f -p₀

a) It asks to find the force

as the man stops the final velocity is zero

         F = 0 - p₀ / t

the speed is directed downwards which is why it is negative, therefore the result is positive

         F = m v₀ / t

         F = 63.5 7.89 / 3.99 10⁻³

         F = 1.26 10⁵ N

b) in this case flex the knees giving a time of t = 0.205 s

          F = 63.5 7.89 / 0.205

          F = 2.44 10³ N

c) The net force is

         F_net = Sum F

         F_net = F - W

         F_net = F - mg

let's calculate

         F_net = 2.44 10³ - 63.5 9.8

         F_net = 1.82 10³ N

since it is positive it is directed vertically upwards

6 0
3 years ago
Which step follows the identification of the problem in the technological design process?
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The answer is research.

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Explanation:

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A 920 kg cannon fires a 3.5 kg shell at initial acceleration of 95 m/s^2. What is the cannon's recoil force?
Mice21 [21]

Answer:

The cannon recoils with a force of 332.5 N

Explanation:

By Newton's third law Recoil force on cannon = Force in shell.

Force in shell = Mass of shell x Acceleration of shell

Mass of shell = 3.5 kg

Acceleration of shell = 95 m/s²

Force in shell = 3.5 x 95 = 332.5 N

Recoil force on cannon = 332.5 N

So, the cannon recoils with a force of 332.5 N

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