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3 years ago

Define the term specific heat.

Chemistry

2 answers:

Vinvika [58]3 years ago

4 0

Answer:

heat

Explanation:

the heat required to raise the temperature of a unit

Whitepunk [10]3 years ago

4 0

Answer: the heat required to raise the temperature of the unit mass of a given substance by a given amount (usually one degree).

Explanation: The answer explains itself

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If two gases are present in a container, the total pressure in the container is equal to

dmitriy555 [2]

Answer: the sum of the partial pressures of the individual gases.

Explanation:

According to Dalton's Law of partial pressure, the total pressure of a mixture of gases is equal to the sum of the partial pressures which each individual gas would exert if it were confined alone in the volume occupied by the mixture.

Hence, Ptotal = P1+ P2

where Ptotal is the total pressure

P1 and P2 are the partial pressures exerted seperately by the individual gases 1 and 2 that make up the mixture.

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3 years ago

A piece of wood has a labeled length value of 63.2 cm. You measure its length three times and record the following data: 63.1 cm

Ulleksa [173]

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

Accepted value is true value.

Measured values is calculated value.

In the question given Accepted value (true value) = 63.2 cm

Given Measured(calculated values) = 63.1 cm , 63.0 cm , 63.7 cm

1) Percent error (%) for first measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.1 cm

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

$Percent error = \frac{\left | 63.2 - 63.1 \right |}{63.2}\times 100$

$Percent error = \frac{0.1}{63.2}\times 100$

$Percent error = 0.00158\times 100$

Percent error = 0.158 %

2) Percent error (%) for second measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.0 cm

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

$Percent error = \frac{\left | 63.2 - 63.0 \right |}{63.2}\times 100$

$Percent error = \frac{0.2}{63.2}\times 100$

$Percent error = 0.00316\times 100$

Percent error = 0.316 %

3) Percent error (%) for third measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.7 cm

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

$Percent error = \frac{\left | 63.2 - 63.7 \right |}{63.2}\times 100$

$Percent error = \frac{\left | -0.5 \right |}{63.2}\times 100$

$Percent error = \frac{(0.5)}{63.2}\times 100$

$Percent error = 0.00791\times 100$

Percent error = 0.791 %

Percent error for each measurement is :

63.1 cm = 0.158%

63.0 cm = 0.316%

63.7 cm = 0.791%

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3 years ago

What procedure could a student use to examine an intensive property of a rectangular block of wood

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An intensive property does not change when you take away some of the sample. The procedures that a student could use to examine the intensive property of a rectangular block of wood are the hardness, color, density and molecular weight.

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Which term best defines the feeding behavior of most gulls?

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1 year ago

Can someone please check my answer??!!!

Ksenya-84 [330]

Answer:

I think its correct

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3 years ago

Read 2 more answers

Define the term specific heat.​

Define the term specific heat.