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3 years ago

How to find the number of neutrons in an atom

1 answer:

7 0

So, to determine the number of neutrons in atom, we only have to subtract the number of protons from the mass number. Take note that the nucleus of an atom is composed of protons and neutrons. And the number of particles present in the nucleus is referred as mass number (Also, called as atomic mass).

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What changes in trade did Europeans hope to bring about by finding sea routes to Asian markets?

Dovator [93]

Answer:

controlled by the Arabs, who brought frankincense and myrrh by camel caravan from South Arabia.

3 0

2 years ago

WHAT IS AN Ionic bond

lidiya [134]

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WHAT IS AN IONIC BOND

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kossel explained that inert gases r inert due to the electronic configuration which contains 8 electrons in their outermost shell

And other elements loss and gain electrons to form ions and to have electronic configuration same as Noble gas and to get stable

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$Mark \:as\: the\: brainlist\: ans\: with \:thanks...$

#SARDAR JI.

6 0

2 years ago

Read 2 more answers

What would be the freezing point of a solution that has a molality of 1.324 m which was prepared by dissolving biphenyl (C12H10)

lbvjy [14]

The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.

A solution is prepared by dissolving biphenyl into naphthalene. We can calculate the freezing point depression (ΔT) for naphthalene using the following expression.

$\Delta T = i \times Kf \times m = 1 \times 6.90 \°C/m \times 1.324m = 9.14 \°C$

where,

i: van 't Hoff factor (1 for non-electrolytes)
Kf: cryoscopic constant
m: molality

The normal freezing point of naphthalene is 80.26 °C. The freezing point of the solution is:

$T = 80.26 \° C - 9.14 \° C = 71.12 \° C$

The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.

Learn more: brainly.com/question/2292439

3 0

2 years ago

Hydrogen peroxide can be prepared by the reaction of barium peroxide with sulfuric acid according to the reaction BaO2(s)+H2SO4(

Vesna [10]

Answer:

VH2SO4 = 145.3 mL

Explanation:

Mw BaO2 = 169.33 g/mol

⇒ mol BaO2 = 53.5g * ( mol BaO2 / 169.33 g BaO2) = 0.545 mol BaO2

⇒according to the reaction:

mol BaO2 = mol H2SO4 = 0.545 mol

⇒ V H2SO4 = 0.545 mol H2SO4 * ( L H2SO4 / 3.75 mol H2SO4 )

⇒V H2SO4 = 0.1453 L (145.3 mL)

6 0

2 years ago

Read 2 more answers

If the bag was made from a metal (like sturdy aluminum foil), do you think it would lose its heat faster or slower than the plas

Luden [163]

I think it would lose its heat faster than the plastic bags because of higher conductivity feature.

<h3>What is conduction?</h3>

Conduction is the process in which heat or electricity is transmitted or transferred through the material of a substance without movement of the material.

We know that metals are good conductors so we can conclude that it would lose its heat faster than the plastic bags bof higher conductivity feature.

Learn more about heat here: brainly.com/question/13439286

5 0

1 year ago